Area is 6000 yd2
LW = 6000
field must be 40 yards longer than its width
L = W + 40
Replace L with W+40 in 1st equation to solve for Width
(W+40)(W) = 6000
W2 + 40W - 6000 = 0
This is a quadratic but is factorable
Factors of -6000 that add to 40 are (100)(-60)
(W+100)(W-60) = 0
W = -100 or W = 60
Since the width will not be negative discard -100
The width is 60 yards
Length is W+40 = 100 yards
Answer:
448
Step-by-step explanation:
A=((a+b)/2) h=(17+39)/2·16=448
Answer:
The answer is 0.6666666667
Step-by-step explanation:
Answer: ± 1.96
Step-by-step explanation:
Given the following :
Mean (m) time spent = 11.85
Standard deviation = 4 minutes
Since the population of site visits is Normally distributed, Hence, the test statistic will follow a normal distribution :
The test the hypothesis that mean time has changed at 0.05 confidence interval
Normal distributions have a mean value of 0 and standard deviation of 1
Using a two tailed test At 0.05 confidence interval ;
Using the critical value calculator, which in general under normal distributions :
0.05% confidence interval for a two tailed test is
± 1.96
