Answer:
Part a)

Part b)

Explanation:
Part a)
For force conditions of two blocks we will have


now from above equations we have


now we know that


now from above equation we have


Part b)
When heavier block is removed and F = 908 N is applied at the end of the string then we have



<span>Kinetic energy increases and potential energy decreases.
</span>
Answer:
The time interval is 
Explanation:
From the question we are told that
The constant acceleration is 
The displacement is
According to the second equation of motion we have that
given that the blade started from rest
which is the initial angular velocity is 0
So
=> 
substituting values
=> 
=> 
The answer is C. Any physical property can be observed without changing the identity of the substance. That’s one of the main things that separates a physical and chemical property.