Answer:
679.08 lbs
Explanation:
Here it is given that

= Mass of first person = 175 pounds
= Height of first person = 70 inches
= Mass of second person
= Height of second person = 110 inches

The weight of the second person would be 679.08 lbs
Answer:
The magnitude of the magnetic field is 1.83 x
T.
Explanation:
The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.
In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.
The magnetic field (B) between the given wires can be determined by:
B = 
where: I is the current, r is the distance between the wires and
is the magnetic field constant.
But, I = 11 A, r = 0.12 m and
= 4
x
Tm/A
So that;
B = 
= 1.8333 x 
B = 1.83 x
T
Answer:
W = 16.5 Kj
P = 49.9 Watt
E = 16471
Explanation:
m = 73.5kg
t = 5min 30sec = (5×60) + 30 = 330sec
each step = 16.6cm = 0.166m
h = 135×0.166 = 22.41 m
g = 10 m/s²
(i) W = F × s = W × h = mgh
W = 73.5×10×22.41 = 16471.35
W = 16.5 Kj
(ii) Power = workdone/time
P = 16471.35/330
P = 49.9 Watt
(iii) The energy burnt in this process = 16471
Answer:
a)a=5.01m/s^2
b)t=11.26s
Explanation:
A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf=Vo+a.t (1)
{Vf^{2}-Vo^2}/{2.a} =X(2)
X=Xo+ VoT+0.5at^{2} (3)
X=(Vf+Vo)T/2 (4)
Where
Vf = final speed
Vo = Initial speed
T = time
A = acceleration
X = displacement
In conclusion to solve any problem related to a body that moves with constant acceleration we use the 3 above equations and use algebra to solve
to solve the question a, we can use the ecuation number 2
Vo=0
Vf=10.5 m/s
x=11m
{Vf^{2}-Vo^2}/{2.a} =X
{Vf^{2}-Vo^2}/{2.x} =a
{10.5^{2}-0^2}/{2x11} =a
a=5.01m/s^2
to find the time we can use the ecuation number 1
Vf=Vo+a.t
t=(Vf-Vo)/a
t=(10.5-0)/5.01=2.09s
part b
in this case the spees is constant, so the movement is defined by the following ecuation
X=VT
t=x/v
t=96.3/10.5=9.17s
to find the total time we sum the times when the speed is constant and when the acceleration is constan
t=9.17+2.09
t=11.26s