Oh ok .so the answer is.....2838384764733 I suggest the method of comparing variables
Answer:
a. to accuse a public official, before an appropriate tribunal. of misconduct in office
<em> </em><em>Base=9cm</em>
<em>height=3</em><em> </em><em>cm</em>
<em>Area</em><em> </em><em>of</em><em> </em><em>parallelogram=b*h</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>9</em><em>*</em><em>3</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>2</em><em>7</em><em>c</em><em>m</em><em>^</em><em>2</em><em>.</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>
Solution:
we are given that
The magnitudes of the moon and Sirius are -12.5 and -1.44 respectively.
we have been asked to find approximately how many times is the moon brighter than Sirius?
The word magnitude is used by the scientist to describe the brightness of moon/star/object etc.
So we can find the brightness by dividing the given values. so we get
Hence we can say
The moon is 8.68 times brighter than Sirius.
Answer:
x is a variable
Step-by-step explanation:
what happens an squared plus B equals C and what I want to do is solve for a so again what we want to do is when we're taking solver a we want to isolate the variable get the variable by itself so the data that need to look at well what is happening on my variable a well you can see me as being multiplied by X and it's being added by B so I need to undo those but we got to make sure we undo them in a certain upper certain order which we call the reverse order of operations which is like the order of operations but the reverse method meaning I'm gonna undo addition or subtraction first so you can see that since my variable a is being added by B I need to undo that by subtracting B and I'll use my subtraction property of equality that's going to now subtract a 0 and then these C minus B are not like terms so I'm going to write ax is equal to C minus B now I need to solve for a so I need to look at and say alright my a is being x over X so the inverse operation of multiplying is dividing by X so therefore have a equals C minus B divided by X now sometimes you could say alright that's correct but we could also divide this X into both of these terms and I'm going to rewrite this in a different form I could say a equals C over X minus B over X alright so what I'm doing is are just dividing those through
hope this helps
