1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
choli [55]
3 years ago
13

On moving day, Guyton needs to rent a truck. The length of the cargo space is , and the height is less than the width. The broch

ure indicates that the truck can hold . What are the dimensions of the cargo space
Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

On moving day, Guyton needs to rent a truck. The length of the cargo space is 10 ft , and the height is 1 ft less than the width. The brochure indicates that the truck can hold 420 ft3 . What are the dimensions of the cargo space? Assume that the cargo space is rectangular shape.

Answer:

The dimensions; width w is 7 ft and height is 6 ft

Step-by-step explanation:

L = 10 ft the length of the cargo space

w = the width of the cargo space

h = the height of the cargo space the height is 1 ft less than the width

h = w - 1

The truck can hold 420 ft^3 - this means the volume of the space V = 420 ft^3

But V = L*w*h

Substitute h = w - 1 into the Volume equation

Therefore,

10*w*(w - 1) = 420

10w^2 - 10w - 420 = 0

By Using quadratic equation formula to solve and considering positive answer,

w = {-b +- √(b^2 - 4ac)}/2a

Where;

a = 10, b = -10 and c = -420

w = {-(-10) +- √(-10^2 - 4(10)(-420)}/2(10)

w = {-(-10) +- 130}/20

w = (10 + 130)/20 = 140/20 = 7

Or

w = (10 -130)/20 = -120/20 = -6

Here,

I take positive answers and the width is 7 ft

Also, from h = w - 1

height = 7 - 1 = 6 ft

You might be interested in
Please help with theses two questions.
Goryan [66]
Yea i have no clue how she can be like a
4 0
3 years ago
Solve for y. Answer to the nearest tenth
AysviL [449]

Answer:

y = 11.5

Step-by-step explanation:

Given 2 secants from an external point to the circle.

Then the product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant, that is

6(6 + y) = 5(5 + 16)

36 + 6y = 5 × 21 = 105 ( subtract 36 from both sides )

6y = 69 ( divide both parts by 6 )

y = 11.5

7 0
2 years ago
It took Max 3.5 hours to cover a certain route walking at a rate of 2.4 mph. How long would it take Max to cover the same route
andrew11 [14]
It would take 2.8 hours ((3.5 hours x 2.4 Mph)/3Mph) hours for Max to cover the same route walking 3 mph. This problem can be solved by using the velocity equation which is the velocity is equal a change in position divided by a change of time. The amount of time can be found assuming that Max walks in a constant velocity from the starting point until the finish point of 8.4 miles distance (3.5 hours x 2.4 mph)<span>.</span>
7 0
3 years ago
{3.1, 4.2, 7.2, 8.4, 12.2}
Romashka-Z-Leto [24]
X + 2 = 6.2
subtract 2 from both sides
x = 4.2
6 0
3 years ago
Question 1 (Multiple Choice Worth 4 points)
VLD [36.1K]

Answer:

In the first expression:

(5^3)^-4 = 5^-12

Step-by-step explanation:

4 0
3 years ago
Other questions:
  • A radio telescope array is in an unpopulated desert region. The array covers a rectangular area that is one fourth square kilome
    10·1 answer
  • Seven friends picked 7 quarts of blueberries. three of the friends will share 4 quarts of blueberries equally. in which group do
    10·1 answer
  • Can someone help me solve these four problems.
    9·2 answers
  • How do you figure out what 13 x 379?
    5·2 answers
  • Arnold began working at a coffee shop on April first. Ms.Ware, his new boss, told Arnold he would earn $2,500 each month if he w
    15·2 answers
  • There are 3,785 milliliters in 1 gallon, and there are 4 quarts in 1
    9·2 answers
  • Is y=3x^2-x-1 a function
    5·1 answer
  • Question
    8·1 answer
  • What is the answer?How do you solve this?
    13·1 answer
  • What is the equation of g(x)?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!