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denis-greek [22]
3 years ago
8

PLEASE help me graph y=-x-5

Mathematics
1 answer:
Artist 52 [7]3 years ago
5 0
The question already gave you the formula in slope-intercept form (y=mx+b). You just need to graph it. Let’s begin with the easy step. The first point is the y-intercept (b) which is -5. Think of it as a point (0,-5), so you input -5 on the y-axis of the graph. After that is the slope, which usually is a fraction symbolizing rise over run. In this case, since the slope is a -x, is is -1 over one, therefore it’s down 1 right 1.
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The perimeter of a rectangular ink pad is 22 centimeters the area is 28 square centimeters
djverab [1.8K]

Answer

W=7

Explanation:

The formula for the perimeter for a rectangle is P = 2L + 2W

The formula for the area of a rectangle is A = LW

where L = length and W = width

P = 22 and A = 28

22 = 2L + 2W

28 = LW

Rewriting the 2nd equation L = 28/W

Substituting this into the first equation

22=2(28/W) + 2W

Reworking the equation to eliminate the denominator

22W = 2(28) + 2W2

22W = 56 + 2W2

and

2W2 - 22W + 56 = 0

Dividing by 2

W2 - 11W + 28 = 0

(W-7)(W-4)

Set each factor equal to 0 and solve each for 0

W = 4, W = 7

then W = 4

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5 0
3 years ago
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pashok25 [27]

Answer:

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4 0
3 years ago
Write an equation in slope-intercept form for the line that passes through (5,0) and is perpendicular to the line described by y
natta225 [31]

For this case we have to;

We have that an equation in slope-intercept form is given by:

y = mx + b

Where:

m is the slope

b is the cut point with the y axis

Also, by definition, two lines are perpendicular when the product of their slopes is -1. That is:m_ {1} * m_ {2} = - 1

We have the line as data: y_ {1} = \frac {-5} {2} x + 6

Then m_ {1} = \frac {-5} {2}

We foundm_ {2}:

m_ {1} * m_ {2} = - 1

\frac {-5} {2} * m_ {2} = - 1

m_ {2} = \frac {-1} {(\frac {-5} {2})}

m_ {2} = \frac {(2) (- 1)} {(- 5) (1)}

m_ {2} = \frac {2} {5}

Thus, y_ {2} = \frac {2} {5} x_ {2} + b_ {2}

We must find b_ {2}:

We know that y_ {2} passes through the point(x_ {2}, y_ {2}) = (5,0)

We substitute the point in the equation of y_ {2}:

0 = \frac {2} {5} (5) + b_ {2}\\0 = 2 + b_ {2}\\b_ {2} = - 2

Thus, y_ {2} = \frac {2} {5} x_ {2} -2

Then the equation in slope-intercept for the line that passes through (5,0) and is perpendicular to the line described by y_ {1} = \frac {-5} {2} x_{1} + 6 is: y_ {2} = \frac {2} {5} x_ {2} -2

Answer:

y_ {2} = \frac {2} {5} x_ {2} -2


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