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Andrej [43]
3 years ago
6

What is the vertex of the absolute value function below?​

Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0

Answer:

(-3, 2).

Step-by-step explanation:

The vertex is the coordinates of the minimum value of the function .

from the graph the vertex is (-3, 2).

puteri [66]3 years ago
4 0

Answer:

<h2>(-3,2)</h2>

Step-by-step explanation:

<h3><em>A vertex is an inflection point where a function changes its direction.</em></h3>

So, to answer this question, we have to find that inflection point where the absolute functions returns.

If you observe the given graph, you will see that such inflection point is at (-3,2). That means the vertex is located in that position.

Therefore, the right answer is provided by the second choice.

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How do you solve this problem step by step: (4x+3)+(-7x+5)=?
zloy xaker [14]

(4x + 3) + ( - 7x + 5)
Remove unnecessary parenthesis

4x + 3 + ( - 7x + 5)
When there is a "+" in front of the parenthesis the expression remains the same

4x  + 3 - 7x + 5
Collect the like terms by subtracting their coefficients

(4 - 7)x
Calculate the difference
- 3x
- 3x + 3  + 5
Add numbers
3 + 5 = 8
Answer:
- 3x + 8
8 0
3 years ago
Rich has a bag of 24 pencils. Each pencil is 19 centimeters long. What is the combined length of the pencils in meters
Roman55 [17]

Multiply the number of pencils by the length to get total centimeters first, then convert to meters:

24 x 19 = 456 cams.

1 meter = 100 cm

Divide total cm by 100 to get meters

456 / 100 = 4.56 meters

8 0
3 years ago
Plz tell me someone know how to do this!!<br> I'll mark brainliest
anygoal [31]

Answer:

It would be the second option

Step-by-step explanation:

z:28 is the ratio of the shorter triangle's side to the larger triangle's side, so is 27:45.

5 0
3 years ago
A train travels 150 km in the same time that a plane covers 525 km. If the speed of the plane is 20 km per hr less than 4 times
babunello [35]

Answer:

Step-by-step explanation:

3 0
3 years ago
Draw the segment PQ with endpoints P(-2, -1) and Q(2,4) on the coordinate plane. Then find the length and midpoint of PQ.
TiliK225 [7]

The graph of the line segment PQ is attached. To find the length, we have to use distance formula which is

d = \sqrt{ (x_{2} -x_{1} )^2 + (y_{2} - y_{1} )^2  }

PQ = \sqrt{ (2-(-2))^2 + (4- (-1))^2 } = \sqrt{ (2+2)^2 + (4+1)^2 }

PQ = \sqrt{16+25} = \sqrt{41}

To find the midpoint,we have to use the formula

( \frac{x_{1}+ x_{2} }{2} ,\frac{y_{1}+ y_{2} }{2} ) = (\frac{-2+2}{2} , \frac{-1+4}{2} )

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4 0
4 years ago
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