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pashok25 [27]
3 years ago
9

In 1929, Farmer Giles took his animals to market. He had some cows, sheep and chickens to sell. Cows sold for ten pounds each. S

heep sold for one pound each. Chickens were sold for one pound for a brood of eight (they were only sold in whole broods). Farmer Giles had a good day and sold 100 animals for exactly £100. The day did have its down side; he had to sell Daisy, his favourite cow. How many sheep did Farmer Giles sell?
Mathematics
2 answers:
MrMuchimi3 years ago
4 0

Answer:

21 sheep

Step-by-step explanation:

100 = x + y + 8z

10x + y + z = 100

x = 1

y + 8z = 99

y + z = 90

x = 2

y + 8z = 98

y + z = 80

x = 3

y + 8z = 97

y + z = 70

x = 4

y + 8z = 96

y + z = 60

x = 5

y + 8z = 95

y + z = 50

x = 6

y + 8z = 94

y + z = 40

x = 7

y + 8z = 93

y + z = 30

7z = 63

z = 9

y = 30 - 9 = 21

x = 7 (7 cows)

y = 21 (21 sheep)

z = 9 (9×8 = 72 chicken)

katrin2010 [14]3 years ago
3 0

Answer:

90 sheep?

Step-by-step explanation:

1 sheep= 1 pound

1 cow= 10 pounds

total amount made= 100 pounds

100 ÷ 1 (the cost for sheep) = 100 sheep

100 - 90 (the cost of cows) = 10

10 sheep

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1 year ago
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3 0
3 years ago
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Some expressions are:

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6 0
4 years ago
3x + 1
VMariaS [17]

Answer:

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