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elixir [45]
3 years ago
9

Simplify. 2a4b5c(4a4bc3)

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
4 0

Answer:

1920 a^2 b^2 c^2

Step-by-step explanation:

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Consider rolling a six-sided die. Let A be the set of outcomes where the roll is an even number. Let B be the set of outcomes wh
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Answer:

See below

Step-by-step explanation:

A = \{2, 4, 6\}

A^c =\{1, 3, 5\}\\B = \{4, 5, 6\}\\B^c = \{ 1,2, 3\}

To prove 1 we have

(A  \bigcup B) = \{2, 4, 6\} \bigcup \{4, 5, 6\} = \{2, 4, 5, 6\}\\(A  \bigcup B) ^c =\bold{\{1,3\}}\\A^c \bigcap B^c = {\{1, 3, 5\}  \bigcap \{1, 2, 3\} =\bold{\{1,3\}}\\

Hence proved

To prove 2

(A \bigcap B) = \{2, 4, 6\} \bigcap \{4, 5, 6\} = \{4, 6\}\\\\(A \bigcap B)^c = \bold{\{1,2, 3, 5\}}\\A^c \bigcup B^c = \{1, 3, 5\} \bigcup  \{1, 2, 3\} = \bold{\{1,2,3,5\}}\

Hence proved

<u>Notes</u>

The complement of a set is the set of all elements <u>not</u> in the set

Here the set of all outcomes is {1, 2, 3,4,5, 6}

So if A = {2, 4, 6} then the complement of A s=is the set of outcomes not in A ie the set {1, 3, 5} which is the set of odd numbers on a die throw

The union of two sets is the set of all elements in both sets without duplication

The intersection of two sets is the set of all elements common to both sets

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