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3 years ago

Solve for x:

Mathematics

2 answers:

astraxan [27]3 years ago

7 0

The answer for this question is 8

Luba_88 [7]3 years ago

6 0

In this problem X is equal to 8

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What is the solution of the equation x2+12x+23=0

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4 years ago

What is the slope of the line? 3(y - 1) = 2x + 2

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3 years ago

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Construct a matrix of order 3×2 whose elements are given by Cij=|−2i+3j|/2

mafiozo [28]

$C_{ij}$ is the entry of $C$ in row $i$ and column $j$ . $C$ has 3 rows and 2 columns, so

$C_{11} = \dfrac{|-2\times1+3\times1|}2 = \dfrac{|-2+3|}2 = \dfrac{|-1|}2 = \dfrac12$

$C_{12} = \dfrac{|-2\times1+3\times2|}2 = \dfrac{|-2+6|}2 = \dfrac{|4|}2 = 2$

$C_{21} = \dfrac{|-2\times2+3\times1|}2 = \dfrac{|-4+3|}2 = \dfrac{|-1|}2 = \dfrac12$

$C_{22} = \dfrac{|-2\times2+3\times2|}2 = \dfrac{|-4+6|}2 = \dfrac{|2|}2 = 1$

$C_{31} = \dfrac{|-2\times3+3\times1|}2 = \dfrac{|-6+3|}2 = \dfrac{|-3|}2 = \dfrac32$

$C_{32} = \dfrac{|-2\times3+3\times2|}2 = \dfrac{|-6+6|}2 = \dfrac{|0|}2 = 0$

Then the matrix is

$C = \begin{bmatrix}\dfrac12 & 2 \\\\ \dfrac12 & 1 \\\\ \dfrac32 & 0\end{bmatrix} = \dfrac12 \begin{bmatrix}1&4\\1&2\\3&0\end{bmatrix}$

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2 years ago

-3-2e-7=10 need help for my brother

sesenic [268]

Question/Equation:

-3-2e-7=10

Answer/steps:

1. Simplify -3-2e-7 to -10-2e.

−10−2e=10

2. Since -10-2e=10 is false, there is no solution.

No Solution

Done by NeighborhoodDealer

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3 years ago

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