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Marysya12 [62]
4 years ago
5

Which is a correct comparison of the fractions? 4/5 and 5/6 A.4/5<5/6 B. 4/5=5/6 C. 4/5>5/6

Mathematics
1 answer:
Masteriza [31]4 years ago
7 0

Hello!


Firstly, we can find the values of the two given fractions, 4/5 and 5/6.


4/5 is equivalent to 0.80

5/6 is equivalent to 0.833...


Choice A, 4/5 < 5/6 is correct. 4/5 is less than 5/6.

Choice B, 4/5 = 5/6 is incorrect, they are not equal to each other.

Choice C, 4/5 > 5/6 is also incorrect, 4/5 is NOT greater than 5/6. It's less than 5/6.

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Find the coordinates of the midpoint of a segment with the given endpoints W(-12, -7), T(-8, -4)
jasenka [17]

Finding the midpoint coordinates of any segment really boils down to finding the midpoints of each individual coordinate.

The x-coordinates of the two points are -12 and -8 - the number halfway between those two is -10, so that'll be the midpoint's x-coordinate. The y-coordinates are -7 and -4 - -5.5 is halfway between these two, so the y-coordinate will be 5.5.

Putting the two together, the midpoint of the segment WT has the coordinates (-10, -5.5).

4 0
3 years ago
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If you were asked to load 225 bixes on a truck , and boxes are crated. With each nine boxes how many crates would you need to lo
Lubov Fominskaja [6]
225 divided by 9 to figure out the number of crates needed.
225/9=25

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4 years ago
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bearhunter [10]
B. triangle and triangular prism
6 0
3 years ago
Given r(x) = 11/ (x - 42)
julsineya [31]

For a given function f(x) we define the domain restrictions as values of x that we can not use in our function. Also, for a function f(x) we define the inverse g(x) as a function such that:

g(f(x)) = x = f(g(x))

<u>The restriction is:</u>

x ≠ 4

<u>The inverse is:</u>

y = 4 + \sqrt{\frac{11}{x} }

Here our function is:

f(x) = \frac{11}{(x - 4)^2}

We know that we can not divide by zero, so the only restriction in this function will be the one that makes the denominator equal to zero.

(x - 4)^2 = 0

x - 4 = 0

x = 4

So the only value of x that we need to remove from the domain is x = 4.

To find the inverse we try with the general form:

g(x) = a + \sqrt{\frac{b}{x} }

Evaluating this in our function we get:

g(f(x)) = a + \sqrt{\frac{b}{f(x)} }  = a + \sqrt{\frac{b*(x - 4)^2}{11 }}\\\\g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4)

Remember that the thing above must be equal to x, so we get:

g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4) = x\\\\{\frac{b}{11 }} = 1\\{\frac{b}{11 }}*4 - a = 0

From the two above equations we find:

b = 11

a = 4

Thus the inverse equation is:

y = 4 + \sqrt{\frac{11}{x} }

If you want to learn more, you can read:

brainly.com/question/10300045

3 0
3 years ago
Could someone please list all of the basic derivative rules?
olchik [2.2K]

Answer:

The sum rule is f' + g'

The difference rule is f' − g'

The product rule is f g' + f' g

The quotient rule is (f' g − g' f )/g2



5 0
3 years ago
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