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nirvana33 [79]
4 years ago
14

Question 1 of 10

Physics
1 answer:
Bad White [126]4 years ago
3 0
The answer is b maybe?
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What is the acceleration of a car that goes from 40km/hr to 80km/hr in 2s?
tresset_1 [31]
Acceleration = v2 - v1 / t
a = 80 - 40 / 2
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In short, Your Answer would be 20 m/s²

Hope this helps!
5 0
3 years ago
When a ball is thrown in the air, the potential energy gained must come from the kinetic energy given by the person throwing the
vodka [1.7K]
I believe it is C. remain the same. If i am wrong i sincerely apologize.
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3 years ago
Read 2 more answers
A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 2.3 cm from the axis of rotation. (a) Calcul
VLD [36.1K]

Answer:

a) a_{r} = 0.275\,\frac{m}{s^{2}}, b) \mu_{s} = 0.028, c) \mu_{s} = 0.036

Explanation:

a) The linear acceleration of the watermelon seed is:

a_{r} = \omega^{2}\cdot r

a_{r} = \left[\left(33\,\frac{rev}{min} \right)\cdot \left(2\pi\,\frac{rad}{rev} \right)\cdot \left(\frac{1}{60}\,\frac{min}{s} \right)\right]^{2}\cdot (0.023\,m)

a_{r} = 0.275\,\frac{m}{s^{2}}

b) The watermelon seed is experimenting a centrifugal acceleration. The coefficient of static friction between the seed and the turntable is calculated by the Newton's Laws:

\Sigma F = \mu_{s}\cdot m\cdot g = m\cdot a

a = \mu_{s}\cdot g

\mu_{s} = \frac{a}{g}

\mu_{s} = \frac{0.275\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }

\mu_{s} = 0.028

c) Angular acceleration experimented by the turntable is:

\alpha = \frac{\omega-\omega_{o}}{\Delta t}

\alpha = \frac{3.456\,\frac{rad}{s}-0\,\frac{rad}{s} }{0.36\,s}

\alpha = 9.6\,\frac{rad}{s^{2}}

The tangential acceleration experimented by the watermelon seed is:

a_{t} = \left(9.6\,\frac{rad}{s^{2}} \right)\cdot (0.023\,m)

a_{t} = 0.221\,\frac{m}{s^{2}}

The linear acceleration experimented by the watermelon seed is:

a = \sqrt{a_{t}^{2}+a_{r}^{2}}

a = \sqrt{\left(0.221\,\frac{m}{s^{2}} \right)^{2}+\left(0.275\,\frac{m}{s^{2}} \right)^{2}}

a = 0.353\,\frac{m}{s^{2}}

The minimum coefficient of static friction is:

\mu_{s} = \frac{0.353\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }

\mu_{s} = 0.036

4 0
3 years ago
A charge of +1.4×10^6 coulombs moves from point a to b. What is the potential difference between the two points if the work done
Rama09 [41]
The potential difference between the two points if the work done on the charge is +3.4×10^7 joules would be A. 10volts.
8 0
3 years ago
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