To solve this problem we will use the equilibrium conditions in the Electrostatic Forces. In turn, we will use the concept formulated from Coulomb's laws to determine the intensity of the Forces and make the respective considerations.
Our values for the two charges are:
As a general consideration we will start by determining that they are at a unit distance (1) separated from each other. And considering that both are negative charges, they will be subjected to repulsive force. Said equilibrium compensation will be achieved only by placing a third force between the two.
Let the third charge be 
is placed at a distance x from 
The force on 
due to 
is
The condition of equilibrium is
from
To find the magnitude of we use 
The magnitude of the third charge must be 0.43 the first charge 
Answer:
322 kJ
Explanation:
The work is the energy that a force produces when realizes a displacement. So, for a gas, it occurs when it expands or when it compress.
When the gas expands it realizes work, so the work is positive, when it compress, it's suffering work, so the work is negative.
For a constant pressure, the work can be calcutated by:
W = pxΔV, where W is the work, p is the pressure, and ΔV is the volume variation. To find the work in Joules, the pressure must be in Pascal (1 atm = 101325 Pa), and the volume in m³ (1 L = 0.001 m³), so:
p = 60 atm = 6.08x10⁶ Pa
ΔV = 82.0 - 29.0 = 53 L = 0.053 m³
W = 6.08x10⁶x0.053
W = 322x10³ J
W = 322 kJ
<span>Answer: 110.12 m/s </span>
We will use the formula A1V1 = A2V2
where 7.8 m/s is divided with 0.0085 m then multiply to 0.12 m, the result will
be 110.117 or 110.12 m/s. This is related to the continuity of fluid flow in
which as liquid moves horizontally, the same amount of liquid goes out as it comes in or the
liquid itself do not change as it moves but the speed does when the diameter changes.
The answer is A) <span>The death rate begins to fall, but birth rates remain high for a time.</span>
