What phase are daughter cells in as a result of mitosis

In a collision between an electron and a hydrogen atom, it is useful to select both objects as the system because which of these

lukranit [14]

Answer:

Explanation:

Because of the following ,it is useful to select both objects as the system during collision between an electron and a hydrogen atom

1. The total momentum of the system does not change during the collision.

2.The forces the objects exert on each other are internal to the system and don't change the total momentum of the system.

3. During the time interval just before to just after the collision, external forces are negligible.

6 0

4 years ago

At what frequency should a 200-turn, flat coil of cross sectional area of 300 cm2 be rotated in a uniform 30-mT magnetic field t

stellarik [79]

Answer:

The frequency of the coil is 7.07 Hz

Explanation:

Given;

number of turn of the coil, N = 200 turn

area of the coil, A = 300 cm² = 0.03 m²

magnitude of magnetic field, B = 30 mT = 0.03 T

maximum value of induced emf, E = 8 V

The maximum induced emf in the coil is given by;

E = NBAω

E = NBA(2πf)

$f = \frac{E_{max}}{2\pi*NBA}$

where;

f is the frequency of the coil

$f = \frac{E_{max}}{2\pi*NBA}\\\\f = \frac{8}{2\pi(200)(0.03)(0.03)} \\\\f = 7.07 \ Hz$

Therefore, the frequency of the coil is 7.07 Hz

5 0

3 years ago

A merry-go-round is spinning at a rate of 4.04.0 revolutions per minute. Cora is sitting 0.50.5 m from the center of the merry-g

dsp73

Answer:

angular speed of both the children will be same

Explanation:

Rate of revolution of the merry go round is given as

f = 4.04 rev/min

so here we have

$f = \frac{4.04}{60} =0.067 rev/s$

here we know that angular frequency is given as

$\omega = 2\pi f$

$\omega = 2\pi(0.067)$

$\omega = 0.42 rad/s$

now this is the angular speed of the disc and this speed will remain same for all points lying on the disc

Angular speed do not depends on the distance from the center but it will be same for all positions of the disc

7 0

3 years ago

a man exerts 3000.00N of force to push a car 35.00 meters in 90.00 seconds.... 1. what is the work done 2.what is the power gene

vaieri [72.5K]

1). Work = (force) x (distance)

Work = (3,000 newtons) x (35 meters) = 105,000 newton-meters = 105,000 joules

2). Power = (work) / (time)

Power = (105,000 joules) / (90 seconds)
= 1,166-2/3 joules per second = 1,166 and 2/3 watts .

Note:
That's no ordinary man.
1,166 watts is the same as roughly 1.6 horsepower.
Not too many people can sustain 1 horsepower or more for 90 seconds.

4 0

4 years ago

a 25 resistor, a 55 resistor, and a 75 resistor are connected in parallel and placed across a 9.0battery.

earnstyle [38]

1644 because it is the awnser

6 0

3 years ago