Answer:
The gravitational force between them is 
.
Explanation:
Given that,
Distance = 1.50 m
Mass of one student = 70.0 kg
Mass of other student = 52.0 kg
We need to calculate the gravitational force
Using formula of gravitational force
Where, m₁ = mass of one student
m₂ = mass of other studen
r = distance between them
Put the value into the formula
Hence, The gravitational force between them is .
Answer:
172.9m
Explanation:
h = 1/2 gt^
First calculat for t using
v = gt
t = v/g = 58.8/10
= 5.88secs
now h = 1/2 x 10 x 5.88^2
h =1/2 x 10 x 34.57
= 345.74/2
= 172.9m
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b. alpha
A baseball is accelerated downward at 9.8 m/s^2 when the only vertical force acting upon the baseball is gravity.
Answer:
d = 0.247 mm
Explanation:
given,
λ = 633 nm
distance from the hole to the screen = L = 4 m
width of the central maximum = 2.5 cm
2 y = 0.025 m
y = 0.0125 m
For circular aperture
using small angle approximation
now,
d =0.247 x 10⁻³ m
d = 0.247 mm
the diameter of the hole is equal to 0.247 mm
