The term "unbalanced force" in Newton's first law refers to a force that is not entirely counterbalanced (or cancelled) by the other independent forces. Basically, magnitude can be thought of as simply the "value" or "amount" of any physical quantity. It is a scalar quantity at all times.
Force has both a magnitude and a direction because it is a vector quantity. The amount that encapsulates the force's strength is known as its magnitude.
Consider the following scenario: the force is 10 N in the east. The direction is indicated by "towards east," while the force is indicated by "10."
Unless acted upon by an unbalanced force, an object at rest tends to stay at rest, and an object in motion tends to stay in motion with the same speed and direction.
The term "unbalanced force" in Newton's first law refers to a force that is not entirely counterbalanced (or cancelled) by the other independent forces. An uneven force exists if either all the vertical forces (up and down) or all the horizontal forces do not cancel each other. Looking at the free-body diagram for a particular situation makes it easy to recognize whether an unbalanced force is present.
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Answer:
0.055 kg
Explanation:
Given that
Length of the string, l = 5 m
Speed of the wave, v = 30 m/s
Tension on the string, F(t) = 10N
From the formula written in the attachment, we have
v = velocity of the wave, in m/s
F(t) = Tension on the string, in N
U = Mass per length of the string, in kg/m
m = Mass of the string, in kg
l = Length of the string, in m
See attachment for the calculation
Answer:
The total work done by the two tugboats on the supertanker is 3.44 *10^9 J
Explanation:
The force by the tugboats acting on the supertanker is constant and the displacement of the supertanker is along a straight line.
The angle between the 2 forces and displacement is ∅ = 15°.
First we have to calculate the work done by the individual force and then we can calculate the total work.
The work done on a particle by a constant force F during a straight line displacement s is given by following formula:
W = F*s
W = F*s*cos∅
With ∅ = the angles between F and s
The magnitude of the force acting on the supertanker is F of tugboat1 = F of tugboat 2 = F = 2.2 * 10^6 N
The total work done can be calculated as followed:
Wtotal = Ftugboat1 s * cos ∅1 + Ftugboat2 s* cos ∅2
Wtotal = 2Fs*cos∅
Wtotal = 2*2.2*10^6 N * 0.81 *10³ m s *cos15°
Wtotal = 3.44*10^9 Nm = <u>3.44 *10^9 J</u>
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The total work done by the two tugboats on the supertanker is 3.44 *10^9 J
Answer:
our acceleration is 0 because there is a constant speed..
a = final speed - initial speed / time
final speed = initial speed ( since speed is constant)
therefore acceleration is 0
Nuclear energy is released during: fission. radioactive decay. man-induced splitting of atoms. Match the basic components of a nuclear reactor with their descriptions. 1. slows down neutrons -> moderator. 2. absorb emitted neutrons -> control rods.
