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Likurg_2 [28]
3 years ago
12

The current through a 10 ohm resistor is 1.2 amperes.What is the potential difference across the resistor?

Physics
1 answer:
Natalija [7]3 years ago
6 0

<u>Answer</u>: The potential difference across the resistor is 12 volts.

<u>Explanation:</u>

To calculate the potential difference cross the resistor, we use Ohm's Law. This law states that the potential difference across two wires is directly proportional to the current flowing through that wire.

Mathematically,

V\propto I\\V=IR

Where,

V = potential difference = ?V

I = Current flowing = 1.2 A

R = Resistor = 10\Omega

Putting values in above equation, we get:

V=1.2\times 10=12V

Hence, the potential difference across the resistor is 12 volts

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Answer:

a

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4 0
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A system consists of three particles with these masses and velocities: mass 3.00 kg, moving north at 3.00 m/s; mass 4.00 kg, mov
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Answer:

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Explanation:

given,

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mass(m₂) 4.00 kg, moving south at v₂ =  3.70 m/s

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north as the positive axis

south as the negative axis

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7 0
3 years ago
If 2.0×10^−4 C of charge passes a point in 2.0×10^−6 s , what is the rate of current flow?1.0×10^−10 A1.0×10^2 A4.0×10^−1 A4.0×1
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This problem is about the rate of the current. It's important to know that refers to the quotient between the electric charge and the time, that's the current rate.

I=\frac{Q}{t}

Where Q = 2.0×10^−4 C and t = 2.0×10^−6 s. Let's use these values to find I.

\begin{gathered} I=\frac{2.0\times10^{-4}C}{2.0\times10^{-6}\sec } \\ I=1.0\times10^{-4-(-6)}A \\ I=1.0\times10^{-4+6}A \\ I=1.0\times10^2A \end{gathered}

<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>

<em />

<h2>Therefore, the rate of the current flow is 1.0×10^2 A.</h2>
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