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Galina-37 [17]
3 years ago
12

What information is necessary to calculate a confidence interval?

Physics
1 answer:
Anni [7]3 years ago
6 0
<span>Write down the phenomenon you'd like to test. ...Select a sample from your chosen population. ...Calculate your sample mean and sample standard deviation. ...Choose your desired confidence level. ...Calculate your margin of error. ...<span>State your confidence interval.</span></span>
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Need help now due in 5 minutes
rjkz [21]

Answer:

I'm positive it's the last one

Explanation:

6 0
4 years ago
If a freely falling object were equipped with a speedometer on a planet where the acceleration due to gravity is 20 m/s², then i
babymother [125]

Answer:

20 m/s

Explanation:

The acceleration of an object determines the increase in velocity per second.

In this case the acceleration is 20m/s^2.

a=\frac{v}{t}=\frac{\frac{20m}{s}}{s}

That is, the increase is 20m/s each second.

I hope this is useful for you

Regards

7 0
4 years ago
Read 2 more answers
Two identical metal balls a and b are mounted on insulating rods. Ball a has a charge of +q/2 and ball b is initially uncharged.
oksano4ka [1.4K]

Answer:

Help me please?

Explanation:

Did you get the answer? I believe it’s either C. +q or D. 0

6 0
3 years ago
Read 2 more answers
What type of particle found inside the atom is uncharged
soldi70 [24.7K]

The neutron is uncharged.  That's why it was
given a name built on "neu" from "neutral".


3 0
3 years ago
Read 2 more answers
How long must a simple pendulum be if it is to make exactly six swings per second? (that is, one complete vibration takes exactl
MA_775_DIABLO [31]
The period of a simple pendulum is given by:
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the length of the pendulum and g is the gravitational acceleration.

The pendulum in our problem makes one complete vibration in 0.333 s, so its period is T=0.333 s. Using this information, we can re-arrange the previous formula to find the length of the pendulum, L:
L= g  \frac{T^2}{(2 \pi)^2}=(9.81 m/s^2) \frac{(0.333 s)^2}{(2 \pi)^2}=0.028 m
6 0
3 years ago
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