Well nick, the velocity at time= 0 it’s zero meter/second.
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Answer:
u=8.868 m/s
Explanation:
The displacement of the ball is 4 meters
The final speed of the ball is 0.5 m/s
The initial speed of the ball is to be calculated. Using the equation of the rectilinear motion,

Plugging the values in the above expression,

Answer:
A. Both rocks will push back at the astronaut with 12 N.
Explanation:
According to 3 rd law of Laws of motion of Newton , there is equal and opposite reaction so both the rocks will exert the same force of 12N on the astronaut separately . Acceleration of both of them will not be equal because their masses are different.
Answer:
Therefore the average speed of a rock launched 700km from a catapult in 15 seconds is 46666.66 m/s or 46.66 km/s.
Explanation:
Given:
Total Distance Covered = 700 km = 700 × 1000 meter = 700000 m
Time taken = 15 seconds = 15 s
To Find:
Average speed of a rock = ?
Solution:
Average speed:
Average speed is defined as the rate of total distance covered in per unit time.
It is given as

Substituting the given values we get

Therefore the average speed of a rock launched 700km from a catapult in 15 seconds is 46666.66 m/s or 46.66 km/s.