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storchak [24]
3 years ago
14

You throw a football straight up. Air resistance can be neglected. When the football is 4.00 mm above where it left your hand, i

t is moving upward at 0.500 m/sm/s. What was the speed of the football when it left your hand
Physics
1 answer:
rosijanka [135]3 years ago
6 0

Answer:

u=8.868 m/s

Explanation:

The displacement of the ball is 4 meters

The final speed of the ball is 0.5 m/s

The initial speed of the ball is to be calculated. Using the equation of the rectilinear motion,

v^{2} =u^{2} +2as

Plugging the values in the above expression,

\\0.5^{2} =u^{2} +2*(-9.8)*4\\\\u^{2} =78.4+0.25\\\\u^{2} =78.65\\\\u=8.868 m/s

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Two resistors in series are often called a 'voltage divider', because the
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The total resistance in the string across the battery is (11 + 6) = 17 ohms.

-- The full battery voltage appears across 17 ohms.
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Multiply each side by (17/6) :      B = (9 volts) x (17/6)  =<em>  25.5 volts </em>.

By the way, in case you care or are asked . . .

-- The current in the whole series loop is  B/R = 25.5 / 17 = 1.5 Amperes
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-- The power dissipated by the 6-ohm resistor is  V²/R = 9²/6 = 13.5 watts
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-- (Check:  13.5W + 24.75W = 38.25W     yay! )
-- If they're just composition units hanging out in the air, then both resistors
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