<span>g = GMe/Re^2, where Re = Radius of earth (6360km), G = 6.67x10^-11 Nm^2/kg^2, and Me = Mass of earth. On the earth's surface, g = 9.81 m/s^2, so the radius of your orbit is:
R = Re * sqrt (9.81 m/s^2 / 9.00 m/s^2) = 6640km
here, the speed of the satellite is:
v = sqrt(R*9.00m/s^2) = 7730 m/s
the time it would take the satellite to complete one full rotation is:
T = 2*pi*R/v = 5397 s * 1h/3600s = 1.50 h
Hope it help i know it's long and may be confusing but if you have any more questions regarding this topic just hmu! :)</span>
Answer:
Explanation:
Deflection in the drop is due to electric field force
so we will have
acceleration of the drop is given as
now we know that time to cross the plates is given as
now the deflection is given as
Answer:
m= 10 kg a = 52 m / s²
Explanation:
For this problem we must use Newton's second law, let's apply it to each axis
X axis
F - fr = ma
The equation for the force of friction is
-fr = miu N
Axis y
N- W = 0
N = mg
Let's replace and calculate laceration
F - miu (mg) = ma
a = F / m - mi g
a = 527.018 / m - 0.17 9.8
We must know the mass of the body suppose m = 10 kg
a = 527.018 / 10 - 1,666
a = 52 m / s²
