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andrey2020 [161]

2 years ago

11

An accurate clock shows 8 o'clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 o'clo

ck in the afternoon?

1 answer:

8_murik_8 [283]2 years ago

3 0

Answer:

im kinda sure the answer is 120 degrees

Step-by-step explanation:

but maybe not

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What is the result of subtracting the second equation from the first?

dusya [7]

Answer: $11x-8y=-9$

Step-by-step explanation:

For this exercise you need to remember:

1) The mulitplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

2) By definition, like terms contain the same variables with the same exponent.

Then knowing this, and given the equations:

$8x - 4y = -4$ and $-3x+ 4y = 5$

You must subtract the like terms, which means that you must subtract the numerical coefficients of each term.

Then, you get the result is:

$8x - 4y = -4\\-3x+ 4y = 5\\...............................................\\8x-(-3x)-4y-4y=-4-5\\8x+3x-8y=-9\\11x-8y=-9$

5 0

2 years ago

Easy question (easy math question)

Ronch [10]

Answer:

4/5

Step-by-step explanation:

because the ratio is 4:5

6 0

2 years ago

Read 2 more answers

Someone please help me with angle relationships in circles with algebra.

Mrac [35]

If angle TSV=6x+17 then arc it intercept (SV)would be double it

6x+17=1/2 (15x+13)
12x+34=15x+13
21=3x
x=7

Arc SV=15(7)+13
=118

And angle TSV=6(7)+17
=59

There are 360 degrees in a circle and the measure of the arc would be equal to the central point so the sum of all the arcs equals 360

Arc SV+ arc SUV=360
118+SUV=360
Arc SUV=242

6 0

2 years ago

Avril invested 60,000 in a partnership with Lane, Jules, Ray, Ravi, and Petra. The total investment of all partners was $320,000

8090 [49]

Answer:

$Percentage\ of\ Avril=18.75\%$

Step-by-step explanation:

Concept Used: Percentage: $x\ amount\ of\ y.\ Percentage=\frac{x}{y}\times 100$

$Total\ investment=\$320000\\\\Avril's\ Investment=\$60000\\\\Percentage\ of\ Avril=\frac{Avril's\ investment}{Total\ investment}\times 100\\\\Percentage\ of\ Avril=\frac{60000}{320000}\times 100\\\\Percentage\ of\ Avril=\frac{60000}{3200}\\\\Percentage\ of\ Avril=18.75\%$

8 0

2 years ago

A principal gathered data about the distance, in miles, that his teachers and bus drivers live from school. The box plots below

Gekata [30.6K]

Answer:

We choose C

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo

Basically, interquartile range represents the width or "dispersion" of the set. [1] The interquartile range is determined by the difference between the top quartile (25% highest) and lower quartile (25% lowest) point of the data set.

From the picture, we can find that:

The interquartile range of the bus drivers is: 20 -10 = 10
The interquartile range of the teachers is: 30 -15 = 15

So the interquartile range of the distances for the bus drivers is 5 miles less than the interquartile range of the distances for the teachers.

We choose C

4 0

2 years ago