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Romashka-Z-Leto [24]
3 years ago
5

write an equation of the line in Slope-intercept form that has a slope of -2/3 and has a Y intercept of -4

Mathematics
1 answer:
N76 [4]3 years ago
7 0

y = -2/3x - 4

simply plug into y = mx+b where m is slope and b is y intercept

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First 4 terms for 5 - 2n
vlabodo [156]

Answer:

3 , 1 , -1 , -3

Step-by-step explanation:

5 - 2n

n = 1 ;  5 - 2n = 5 - 2*1 = 5 - 2 = 3

n = 2;  5 - 2n = 5 - 2*2 = 5 - 4 = 1

n = 3;  5 - 2n = 5 - 2*3 = 5 - 6 = -1

n = 4;  5 -2n = 5 - 2*4 = 5 - 8 = -3

First 4 terms are :  3 , 1 , -1 , -3

6 0
3 years ago
Complete the table and graph the coordinates pls sumone just tell me what to put in the table bc i ik how to do the graph brainl
denis23 [38]

Answer:

tbh what grade is this

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
A function LaTeX: f\left(x\right)=\sqrt[3]{x}f ( x ) = x 3 is transformed into the function LaTeX: g\left(x\right)=-\sqrt[3]{x}-
shtirl [24]

Answer:

A reflection in the x-axis, and a vertical translation of 8 units down

Step-by-step explanation:

The given function is

f(x) =  \sqrt[3]{x}

The transformed function is

g(x) =  -  \sqrt[3]{x}  - 8

To see the transformation that occurred, we can rewrite g(x) in terms of f(x).

That is:

g(x) =  - f(x) - 8

Therefore f(x) is reflected in the x-axis and translated 8 units down.

The resulting graph decreases from left to right over its entire domain.

7 0
3 years ago
Which of the following inequalities matches the graph?
Alik [6]
A vertical line has an equation of the form x = k, where k is the x-coordinate of all points on the line.
You have a vertical line. It passes through the point (-3, 0), so for this line, k = -3.
The vertical line has equation x = -3.
The line is dashed, not solid, so you have either < or >, but not <= or >=.
Also, notice the shading is to the left of x = -3, so all values of x are less than -3.
The inequality is

x < -3
8 0
2 years ago
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