Answer:
2.67 moles of cesium carbonate (Cs2CO3).
Explanation:
We'll begin by writing the equation for the reaction. This is illustrated below:
Cs + Fe2(CO3)3 —> Cs2CO3 + Fe
The above equation can be balance as follow:
There are 2 atoms of Fe on the left side and 1 atom on the right side. It can be balance by putting 2 in front of Fe as shown below:
Cs + Fe2(CO3)3 —> Cs2CO3 + 2Fe
There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by 3 in front of Cs2CO3 as shown below:
Cs + Fe2(CO3)3 —> 3Cs2CO3 + 2Fe
There are 6 atoms of Cs on the right side and 1 atom on the left. It can be balance by putting 6 in front of Cs as shown below:
6Cs + Fe2(CO3)3 —> 3Cs2CO3 + 2Fe
Thus, the equation is balanced.
From the balanced equation above,
6 moles of Cs reacted with 1 mole of Fe2(CO3)3 to produce 3 moles of Cs2CO3.
Finally, we shall determine the moles of cesium carbonate (Cs2CO3) produced by the reaction of 5.34 moles of cesium (Cs). This can be obtained as follow:
From the balanced equation above,
6 moles of Cs reacted to produce 3 moles of Cs2CO3.
Therefore,
5.34 moles of Cs will react to produce = (5.34 × 3)/6 = 2.67 moles of Cs2CO3.
Thus, 2.67 moles of cesium carbonate (Cs2CO3) were produced from the reaction.
