Concentration of vinegar sample of 28mL which requires 21. 5 ml of 0.550 M NaOH to reach the endpoint in a titration is 0.42M.
<h3>How do we calculate the concentration of Vinegar?</h3>
Concentration of vinegar in the titration method will be used by using the below equation:
M₁V₁ = M₂V₂,
- M₁ & V₁ are the molarity and volume of acetic acid.
- M₂ & V₂ are the molarity and volume of vinegar sample.
By putting values on above equation from the question, we get
M₂ = (0.55M)(21.5mL) / (28mL) = 0.42 M
Hence, required concentration of vinegar is 0.42M.
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Answer: 3.13 g
Explanation:
Radioactive decay follows first order kinetics.
Half-life of uranium-232 = 68.8 years
N = amount left after time t
= initial amount
= rate constant
t= time
= 100 g, t= 344 years, 
N=3.13g
Evaporating? But that’s with a boiling liquid
The element that has been oxidized is Al ( Answer A)
Explanation
if the oxidation number of an element is greater in the product side than the reactant side then the element has lost the electrons . This mean that the element has been oxidized.
Al is oxidized because it move from oxidation state Zero(0) in reactant side to oxidation state 3⁺ in product side.
This implies that Al loses 3 electrons.
