Question

I need help on this one for an exam real quick please​

Answer 1

Answer:

See Explanation

Explanation:

In the first case, when potassium iodide is added to an aqueous bromine solution, a chemical reaction occurs as follows;

Br2(l) + 2 KI(aq) = 2 KBr(aq) + I2(l)

This reaction produces iodine solution which is brown in colour.

Secondly, when potassium iodide is added to aqueous chlorine solution, the following reaction occurs;

2KI(aq) + Cl2(l)→ 2KCl(aq) + I2 (l)

This reaction also yields iodine solution which is brown in colour.

KI(aq) + I2(l) -------->K^+(aq) + I3^-(aq)

The  I3^-(aq) solution appears brown at high concentrations.