Answer:
See Explanation
Explanation:
In the first case, when potassium iodide is added to an aqueous bromine solution, a chemical reaction occurs as follows;
Br2(l) + 2 KI(aq) = 2 KBr(aq) + I2(l)
This reaction produces iodine solution which is brown in colour.
Secondly, when potassium iodide is added to aqueous chlorine solution, the following reaction occurs;
2KI(aq) + Cl2(l)→ 2KCl(aq) + I2 (l)
This reaction also yields iodine solution which is brown in colour.
KI(aq) + I2(l) -------->K^+(aq) + I3^-(aq)
The I3^-(aq) solution appears brown at high concentrations.
