Answer:
AA similarity theorem
Step-by-step explanation:
we know that
<u>AA (Angle-Angle) Similarity</u> states that In two triangles, if two pairs of corresponding angles are congruent, then the triangles are similar
In this problem we have that
∠BCA=∠ECD ----> by vertical angles
∠BAC=∠DEC ---> because AB is parallel to ED (alternate interior angles)
therefore
Triangles ABC and EDC are similar by AA similarity theorem
Answer:
- x = 30°
- RS = 30°, SR = TU = 120°, UR = 90°
- ∠P = 45°
- ∠UTS = 60°
Step-by-step explanation:
(a) If RS = x, then the sum of arcs around the circle is ...
x + 4x +4x +3x = 360°
12x = 360°
x = 30°
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(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°
- RS = 30°
- ST = 120°
- TU = 120°
- UR = 90°
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(c) Angle P is half the difference of arcs TU and RS:
∠P = (TU -RS)/2 = (120° -30°)/2
∠P = 45°
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(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...
∠UTS = 120°/2 = 60°
90° - 59° = 31°
31° is your answer
Answer:
-3/4 g =x
Step-by-step explanation:
g=-4x/3
Multiply each side by 3
3g = -4/3 x *3
3g = -4x
Divide each side by -4
3/-4 g = -4x/-4
-3/4 g =x