Answer: m∠1 = 128°, m∠2 = 26° and m∠3 = 26°.
Step-by-step explanation: We are given to find the measures of ∠1, ∠2 and ∠3 in the figure.
As shown in the attached figure, ABCD is a rhombus, where m∠A = 128°.
We know that, in a rhombus, all the sides are congruent, the opposite angles are congruent and the adjacent angles are supplementary.
So, from rhombus ABCD, we have
![m\angle A=m\angle C~~~~~\textup{[opposite angles]}\\\\\Rightarrow m\angle 1=128^\circ.](https://tex.z-dn.net/?f=m%5Cangle%20A%3Dm%5Cangle%20C~~~~~%5Ctextup%7B%5Bopposite%20angles%5D%7D%5C%5C%5C%5C%5CRightarrow%20m%5Cangle%201%3D128%5E%5Ccirc.)
Also, in ΔBCD, we have
![BC=CD~~\textup{[all the sides are congruent]}\\\\\Rightarrow m\angle 3=m\angle 2~~\textup{[angles opposite to congruent sides care congruent]}.](https://tex.z-dn.net/?f=BC%3DCD~~%5Ctextup%7B%5Ball%20the%20sides%20are%20congruent%5D%7D%5C%5C%5C%5C%5CRightarrow%20m%5Cangle%203%3Dm%5Cangle%202~~%5Ctextup%7B%5Bangles%20opposite%20to%20congruent%20sides%20care%20congruent%5D%7D.)
Now, since the sum of three angles of a triangle is 180°, we have from ΔBCD that
![m\angle 1+m\angle 2+m\angle 3=180^\circ\\\\\Rightarrow 128^\circ+m\angle 2+m\angle 2=180^\circ\\\\\Rightarrow 2\times m\angle 2=180^\circ-128^\circ\\\\\Rightarrow 2\times m\angle 2=52^\circ\\\\\Rightarrow m\angle 2=26^\circ.](https://tex.z-dn.net/?f=m%5Cangle%201%2Bm%5Cangle%202%2Bm%5Cangle%203%3D180%5E%5Ccirc%5C%5C%5C%5C%5CRightarrow%20128%5E%5Ccirc%2Bm%5Cangle%202%2Bm%5Cangle%202%3D180%5E%5Ccirc%5C%5C%5C%5C%5CRightarrow%202%5Ctimes%20m%5Cangle%202%3D180%5E%5Ccirc-128%5E%5Ccirc%5C%5C%5C%5C%5CRightarrow%202%5Ctimes%20m%5Cangle%202%3D52%5E%5Ccirc%5C%5C%5C%5C%5CRightarrow%20m%5Cangle%202%3D26%5E%5Ccirc.)
Therefore, m∠3 = 26°.
Thus, m∠1 = 128°, m∠2 = 26° and m∠3 = 26°.