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2 years ago

Find the sum of -10x^2-x+6−10x 2 −x+6 and 10x^2-510x 2 −5.

Mathematics

2 answers:

irina [24]2 years ago

8 0

Answer:

1. -10x^2-x+6-10x 2-x+6 = -10x^2 - 22x + 12

2. 10x^2-510x 2-5 = 10x^2 - 1020x - 5

Step-by-step explanation:

hope this helps

if i did something wrong let me know so i can fix my answer

#Virgo2007

Lunna [17]2 years ago

8 0

Answer:

Step-by-step explanation:

(-10x^2-x+6−10x 2 −x+6) + (10x^2-510x 2 −5)

= -10x^2-2x-8+10x^2-1025

= -2x - 1033

correct me if I'm wrong

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Read 2 more answers

Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col

natali 33 [55]

Answer:

$\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]$

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

$\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]$

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

$A^{-1}$ = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = $\left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]$

$A^{-1}$ = $\frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right]$ = $\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]$

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