Answer:
int half(int x){
int a=x/2;
return a;
}
Explanation:
function <em>half(x)</em> which has return type <em>integer</em> and accept an <em>integer </em>type parameter <em>'x'</em> and return the an <em>integer </em>value in variable <em>'a' </em>which is closest to <em>half</em> that of the parameter '<em>x'</em>.
The program which would help Eva convert a Lisp file into machine code by interpreting only a single line of code at a time is: A. interpreters
Interpreters can be defined as computer software programs that are designed to translate (interpret) a programming language (code) into machine code, especially by interpreting only a single line of code at a time.
Hence, an interpreter executes the instructions that are written in a programming language (code) one after the other (instruction by instruction), before it translate (interpret) the next line of code.
On the other hand, a compiler takes the entire program (code) and interprets them.
In conclusion, an interpreter can help Eva convert a Lisp file into machine code by interpreting only a single line of code at a time.
Rea d more: brainly.com/question/21130620
No personal web..............
The difference is that Dropbox offers just 2 GB free storage space while Microsoft's OneDrive gives 5 GB in terms of free storage space.
<h3>What is Microsoft OneDrive?</h3>
This is known to be a file hosting software and it also does synchronization service given by Microsoft.
Some other fundamental difference between Dropbox and OneDrive in terms of Business is that Dropbox is known to often give unlimited storage for about $20 to paid user/month while OneDrive is said to only give unlimited storage for $10 per paid user/month.
Learn more about Dropbox from
brainly.com/question/20935392
Answer:
Explanation:
The following code is written in Java. Both functions traverse the linkedlist, until it reaches the desired index and either returns that value or deletes it. If no value is found the function terminates.
public int GetNth(int index)
{
Node current = head;
int count = 0;
while (current != null)
{
if (count == index)
return current.data;
count++;
current = current.next;
}
assert (false);
return 0;
}
public int removeNth(int index)
{
Node current = head;
int count = 0;
while (current != null)
{
if (count == index)
return current.remove;
count++;
current = current.next;
}
assert (false);
return 0;
}
