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1 answer:
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Answer:
Graph B
No
Inside
Step-by-step explanation:
Let, the number of apples = x and number of peaches = y.
It is given that the farmer can afford maximum of 54 acres.
Thus, x + y ≤ 54.
Also, apples require 3000 gallons of water and peaches require 800 gallons of water each day.
Since, maximum amount of water is 80,000 gallons per day,
We get, 3000x + 800y ≤ 80,000.
It is required to maximize the profit given by z = 3400x + 1600y.
Thus, the system of equations becomes,
z = 3400x + 1600y
3000x + 800y ≤ 80,000.
x + y ≤ 54.
Plotting these equations gives the following graph.
We can see that the graph obtained is equivalent to Graph B.
Further, we know that the maximum value of the objective function z = 3400x + 800y is obtained at the boundary point of the solution region.
Thus, any point inside the solution region will give a feasible solution not maximum solution.
Hence, ( 30,20 ) will not maximize the profit as it lies inside the solution region.
Answer:
the price of good x in 1999 dollars is 370.89 dollars
Step-by-step explanation:
Given that good x sold for $40 in 1945. the Cpi in 1945 was 18.0 and the cpi in 1999 was 166.6.
We have cpi and sale price have direct variation
In other words S = kC where C = CPi and S = sales price
In 1945, 40 = 18k or K = 20/9
Using this we can say
Sales price in 1999 would be k (166.6)
=
the price of good x in 1999 dollars is 370.89 dollars