Hey there!
Na + FeBr₂ → NaBr + Fe
Firstly, balance Br.
Two on the left, one on the right. Add a coefficient of 2 in front of NaBr.
Na + FeBr₂ → 2NaBr + Fe
Next, balance Na.
One on the left, two on the right. Add a coefficient of 2 in front of Na.
2Na + FeBr₂ → 2NaBr + Fe
Lastly, balance Fe.
One on the left, one on the right. Already balanced.
Our final balanced equation:
2Na + FeBr₂ → 2NaBr + Fe
Hope this helps!
Answer:
Explanation:
From the given information:
The density of O₂ gas =
here:
P = pressure of the O₂ gas = 310 bar
=
= 305.97 atm
The temperature T = 415 K
The rate R = 0.0821 L.atm/mol.K
molar mass of O₂ gas = 32 g/mol
∴
= 287.37 g/L
To find the density using the Van der Waal equation
Recall that:
the Van der Waal constant for O₂ is:
a = 1.382 bar. L²/mol² &
b = 0.0319 L/mol
The initial step is to determine the volume = Vm
The Van der Waal equation can be represented as:
where;
R = gas constant (in bar) = 8.314 × 10⁻² L.bar/ K.mol
Replacing our values into the above equation, we have:
After solving;
V = 0.1152 L
∴
= 277.77 g/L
We say that the repulsive part of the interaction potential dominates because the results showcase that the density of the Van der Waals is lesser than the density of ideal gas.
Answer: The reaction has a lower activation energy with the catalyst present than it has without it.
Explanation:
If you project both curves on the Y axis, which represents the amount of energy required for activating the reaction, you can see that the red curve has a lower value than the black curve. This makes perfect sense, since the purpose of a catalyst is of lowering the energy required for activating a reaction.
Answer:
0.6 moles of CaO will produced.
Explanation:
Given data:
Mass of calcium = 23.9 g
Moles of CaO produced = ?
Solution:
Chemical equation:
2Ca + O₂ → 2CaO
Number of moles of calcium:
Number of moles = mass/ molar mass
Number of moles = 23.9 g / 40 g/mol
Number of moles = 0.6 mol
Now we will compare the moles of calcium and CaO.
Ca : CaO
2 : 2
0.6 : 0.6
0.6 moles of CaO will produced.
Lol I don’t have snap. But I’m only texting this cause this app wants me to answer some questions. But! Lol have a great day/night