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4 years ago

If you were running an experiment to determine the temperature at which

Chemistry

1 answer:

dexar [7]4 years ago

8 0

Answer:

Well, it would be the height of the plant. The independant varibles would be the amount of water you give the beans or the temperature you keep them!

Explanation:

I hope this helps!

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How many electrons are located in the 2p sublevel in a ground-state nitrogen atom?

Contact [7]

3 electrons are located in the 2p level

7 0

4 years ago

HELPPPPP A pearlfish spends the day inside the alimentary tract, or intestines, of a sea cucumber. The fish emerges from the sea

Makovka662 [10]

Answer:

D) Bees and plants or sea anemonies and clownfish.

i think..

Explanation:

5 0

3 years ago

Describe why estimating the age of the Sun can give an approximate age of the Earth.

ch4aika [34]

Because the earth wouldn't be able to exist without the help of the sun, the sun is essential for earth.

6 0

3 years ago

1.4g of calcium oxide obtained by heating limestone was found to contain 0.4g of oxygen.another sample of 3.5g of calcium oxide

Leya [2.2K]

Answer:

Solution

1.4 gm of CaO⟶n0.4 gm of Oxygen

1.0 gm of O2⟶3.5 gm of Ca

According to the law of definite proportions

n/m=y/x

⇒1.4/0.4=3.5.

⇒3.5=3.5

Explanation:

6 0

3 years ago

Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation: N2 1 g 2 1 3H2 1 g

bekas [8.4K]

Answer:

Mass of NH3 produced = 1217 g or 1.217*10^3 g

Explanation:

Given:

Mass of N2 = 1.003*10^3 g

Mass of H2 = 5.003*10^2 g

To determine:

Maximum mass of NH3 that can be produced when the given amounts of N2 and H2 combine

Calculation:

The chemical reaction corresponding to the production of ammonia is:

$N2(g)+3H2(g)\rightarrow 2NH3(g)$

Based on the reaction stoichiometry:

1 mole of N2 combines with 3 moles of H2 to form 2 moles of NH3

$moles\ of\ N2 = \frac{Mass\ N2}{Molar\ mass N2} = \frac{1.003*10^{3}g }{28g/mol} =35.8\ moles$

$moles\ of\ H2 = \frac{Mass\ H2}{Molar\ mass H2} = \frac{5.003*10^{2}g }{2g/mol} =250\ moles$

Since the moles of N2 is less than that of H2, the limiting reagent will be N2 which would in turn determine the amount of NH3 formed.

Based on the reaction stoichiometry the N2 : NH3 ratio = 1:2

Therefore,

$moles\ of\ NH3\ produced = 2*35.8 = 71.6\ moles\\\\Mass\ of\ NH3\ produced = moles*molar mass = 71.6\ moles*17\ g/mol = 1217 g$

8 0

4 years ago