Answer:
Reverse the 
reaction
Explanation:
Reactions:
Overall:
As can be seen, in the overall reaction we have 
in the reactants like in the second reaction and 
in the products. The is in the first reaction but as a reactant so we need to reverse that reaction:
Combining:
More positive ions shows acidic whereas more negative ions indicates basic solution.
<h3>Which charge show acidic solution?</h3>
That side which has more positive charges is considered as acidic solution while on the other hand, that region where negative charges are present in large number as compared to positive charges is considered as basic or alkaline solution.
So we can conclude that more positive ions shows acidic whereas more negative ions indicates basic solution.
Learn more about charge here: brainly.com/question/25923373
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Well, gold is way different form other say for instance what if you get a really good ring not to expensive or cheap, but its in between those characteristics what if u get a gold ring to compare now one might tarnish or fade, but if you really look at it that gold one will not it really all dependents on what metals your talking about cause all metals aren't the same some fade and some don't . Also the oxygen level is weak for other metals, but gold it different it can still keeps its shine .
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Answer:
Mechanical Energy to Thermal Energy
When you strike a match, it moves through the air until it rubs against a surface. The rubbing produces the heat required to light the match. This is a transformation from mechanical energy to thermal (heat) energy.
Explanation:
Answer is: mass of silver chloride is 34,82 g.
Chemical
reaction: AgNO₃ +
NaCl → AgCl + NaNO₃.
<span>m(AgNO</span>₃) = 53,42 g..<span>
m(NaCl) = 14,19 g.
n(AgNO</span>₃) = m(AgNO₃) ÷ M(AgNO₃).<span>
n(AgNO</span>₃) = 53,42 g ÷ 169,87 g/mol.
n(AgNO₃) = 0,314 mol.
n(NaCl) = 14,19 g ÷ 58,4 g/mol.
n(NaCl) = 0,242 mol; limiting reactant.
From chemical reaction: n(NaCl) : n(AgCl) = 1 : 1.<span>
n</span>(AgCl)<span> = 0,242 mol.
m</span>(AgCl) = 0,252 mol · 143,32 g/mol.
m(AgCl) = 34,82 g.
