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tensa zangetsu [6.8K]
3 years ago
9

What is the name of the people who hid the Dead Seas Scrolls. When did they live at Qumran?

Chemistry
1 answer:
Shkiper50 [21]3 years ago
3 0
It was named the Qumran seas scrolls.
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How do you convert from grams to moles?
ludmilkaskok [199]

Each element or compound has a molar mass, which is calculated by multiplying the atomic mass of each element by the amount of atoms of that element, and summing the results of each element. The molar mass is measured in g/mol. So you divide the mass in grams by the molar mass to get the amount of moles.

Example:

There are 5g of water.

Calculate the amount of moles.

The water's formula is H2O, so the molar mass of it is

2 \times 1 + 1 \times 16 = 18

g/mol.

The amount of moles is:

5g ÷ 18g/mol ~ 0.28mol

5 0
3 years ago
Which classification best describes oxygen gas? a element b compound c solution d heterogeneous mixture
NNADVOKAT [17]

Answer:

oxygen is an element because it is a pure substance which cannot be split into simpler substances by chemical means

4 0
3 years ago
What is the mass of 0.46 mol of MgCl2
Ronch [10]

Answer:

43.7

Explanation:

mole is equal mass concentration/ moler mass of MgCl²

8 0
3 years ago
In a chemical reaction, what is defined as the difference between the potential energy of the products and the potential energy
zlopas [31]
I Believe That The Answer Is A 
Hope This Helps !

6 0
3 years ago
Read 2 more answers
How much energy is required to heat 36.0 g H2O from a liquid at 65°C to a gas at 115°C? The following physical data may be usefu
In-s [12.5K]

Answer:

energy required=qnet=87.75kJ

Explanation:

we will do it in three seperate step and then add up those value.

first step is to heat the sample of water upto 100C i.e upto boiling pont. because just after this sample of water started vaporization.

q 1= m c (T2-T1)

q1 = 36.0 g (4.18 J/gC) (100 - 65 C)

q1 = 5267 J =5.267kJ

next is to vaporize the sample at 100C

q2 = 36.0 g / 18.0 g/mol X 40.7 kJ/mol

q2= 81.4 kJ

Finally, heat the steam upto 115C

q3 = m c (T2-T1)

q 3= 36.0 g (2.01 J/gC)(115-100C)

q3 = 1085 J =1.085kJ

qnet=q1 +q2 +q3

energy required=qnet=87.75kJ

8 0
3 years ago
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