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zhuklara [117]
4 years ago
11

What do you add to a base to weaken it

Chemistry
1 answer:
lesantik [10]4 years ago
6 0

Answer:

you dont do anything because then you are supporting it

if u add something

Explanation:

You might be interested in
Which expression correctly represents a balanced reduction half-reaction?
jolli1 [7]
For answering for the question, there exists four choices:
1) Na+  +  e- -------------- Na
2) Na --------Na+   +  e-
3) Cl2 +   2e-  ------------ Cl-
4) 2Cl-  ---------Cl2 +  2e-

reduction half-reaction general formula is 
oxidant + e - or +  -------- Product

so in our case the answer is 
1) Na+  +  e- -------------- Na (exactly balanced)

6 0
3 years ago
How does the modern periodic table arrange elements?
Norma-Jean [14]
<span>The </span>elements are arranged<span> in order of increasing atomic number. Vertical columns(called groups) contain </span>elements with similar properties. Horizontal rows called periods elements with<span> the same number of atomic orbitals(That's why Hydrogen and Helium are separated from the rest of the table).

Hope this helps:)</span>
7 0
3 years ago
Read 2 more answers
Why knowing the density of water important?? explain why please so I can understand it don’t copy for the internet I won’t under
Mkey [24]

Answer:

it allows us to determine whether objects will float or sink when placed in a liquid or even a gas.

Explanation:

For example, In an oil spill in the ocean, the oil rises to the top because it is less dense than water, creating an oil slick on the surface of the ocean. A Styrofoam cup is less dense than a ceramic cup, so the Styrofoam cup will float in water and the ceramic cup will sink.

3 0
2 years ago
For the equilibrium
Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

H_2S=0.596M

H_2=0.004 M

S_2=0.002 M

Explanation:

We are given that  for the equilibrium

2H_2S\rightleftharpoons 2H_2(g)+S_2(g)

k_c=9.0\times 10^{-8}

Temperature, T=700^{\circ}C

Initial concentration of

H_2S=0.30M

H_2=0.30 M

S_2=0.150 M

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles  of reactant reduced and form product

Concentration of

H_2S=0.30+2x

H_2=0.30-2x

S_2=0.150-x

At equilibrium

Equilibrium constant

K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Substitute the values

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

By solving we get

x\approx 0.148

Now, equilibrium concentration  of gases

H_2S=0.30+2(0.148)=0.596M

H_2=0.30-2(0.148)=0.004 M

S_2=0.150-0.148=0.002 M

3 0
3 years ago
When ionic compounds are added to water, they dissociate or break apart into ions. In the case of table salt, salt added to wate
Lostsunrise [7]

Answer:

b dissociate

Explanation:

5 0
3 years ago
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