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docker41 [41]
3 years ago
5

How long dose it take to travel 5km at an average speed of 8 m/s? Give your answers in minutes and seconds

Mathematics
1 answer:
eduard3 years ago
4 0

Answer:

625 seconds and 10 minutes

Step-by-step explanation:

distancs=S=5km=5000m

average speed=v=8m/s

time taken=t=?

as we know that

average speed=\frac{distance covered}{time taken}

average speed×time taken=distance covered

here we have to find the time taken

time taken=\frac{distance covered}{average speed}

time taken=\frac{5000m}{8m/s}

time taken=625seconds

now we convert seconds into minutes

\frac{625}{60}

10 minutes

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Jade practices tennis for 3.5 hours. Hayley only spends 0.75 hour practicing
aniked [119]

Answer:

2.75 hours

Step-by-step explanation:

3.5-0.75 which is 2.75.

So 2.75 hours.

Hope this helps :D

3 0
3 years ago
Write an equation for eight times a number decreased by 25 is -1
GarryVolchara [31]
8x3 = 24, 25-24 = -1
4 0
3 years ago
What is the volume formula for this?
Keith_Richards [23]
V=(3.14)(r^2)(h)  ----> v=(3.14)(10^2)(5) ----> V= 1570.8
8 0
3 years ago
a set of five numbers has a mode of 24 a median of 21 a mean of 20 . work out what the numbers could be
SSSSS [86.1K]

Answer:

Step-by-step explanation:

The mode is 24 so we know that at least 2 of the 5 numbers are 24.

The mean is 20 so we know that the 5 numbers add up to 100.

The median is 21 so the third number is 21.

100-(24+24+21)= 31

Now, I am pretty certain that the last 2 numbers can be anything as long as they add up to 31 AND they are not also 21 because 24 then would no longer be the mode.

E.g. 24, 24, 21, 11 & 20

7 0
3 years ago
PLEASE HELP RIGHT AWAY, <br> THANK U SO MUCH!! &lt;3
vredina [299]

Answer:

1. Ans;

{a}^{7}  \times  {a}^{12}  =  {a}^{7 + 12}  =  {a}^{19}

__o_o__

2. Ans;

\frac{ {h}^{6} }{ {h}^{2} }  =  {h}^{4}

__o_o__

3. Ans;

{e}^{6}  \times  {e}^{6}  =  {e}^{6 + 6}  =  {e}^{12}

__o_o__

4.Ans;

\frac{ {w}^{9} }{ {w} }  =  {w}^{8}

__o_o__

5. Ans;

{g}^{2}  \times  {h}^{3}  \times  {g}^{2}  \times h =  {g}^{2 + 2}  \times  {h}^{3 + 1}  =  {g}^{4}  {h}^{4}

__o_o__

6.Ans;

\frac{10 {a}^{12} }{ 6{a}^{3} }  =  \frac{5 {a}^{9} }{3}

__o_o__

7.Ans;

({m}^{4} )^{5}  =  {m}^{4 \times 5}  =  {m}^{20}

__o_o__

8.Ans;

{(3 {a}^{2} })^{3}  = ( {3})^{3}  ( {a}^{2} ) ^{3}  = 27 {a}^{6}

__o_o__

9.Ans;

{( \frac{c}{k} })^{4}  =  \frac{ {c}^{4} }{ {k}^{4} }

__o_o__

10.Ans;

{( \frac{8x}{9} })^{2}  =  \frac{( {8x})^{2} }{ ({9})^{2} }  =  \frac{64 {x}^{2} }{81}

__o_o__

11.Ans;

4 {c}^{2}  \times  {c}^{3}  = 4 {c}^{2 + 3} = 4 {c}^{5}

__o_o__

12.Ans;

{( - 9 {h}^{4}  {k}^{6} })^{2}  =  {( - 9)}^{2}   {( {h}^{4} })^{2}  {( {k}^{6} })^{2}  = 81 \:  \:  {h}^{8}  {k}^{12}

__o_o__

13.Ans;

( { \frac{2d}{3e} })^{3}  =   \frac{ {(2d)}^{3} }{ ({3e)}^{3} }   =  \frac{8 {d}^{3} }{27 {e}^{3} }

__o_o__

14. Ans;

{( \frac{4}{ {w}^{5} }) }^{3}  =  \frac{ ({4)}^{3} }{( {w}^{5} ) ^{3} }  =  \frac{64}{ {w}^{15} }

_____o___o_____

\frac{5 {v}^{4} \times 4 {v}^{5}  }{2 {v}^{3} }  =  \frac{20 {v}^{4 + 5} }{2 {v}^{3} } =  \frac{20 {v}^{9} }{2 {v}^{3} }   = 10 {v}^{6}

_o_o_

( \frac{3 {f}^{4}h}{4 {h}^{9} } ) ^{3}  =  \frac{( {3})^{3} ( {f}^{4})^{3}  ({h})^{3} }{ {(4)}^{3} ( {h}^{9})^{3}  }   \\  \\  \\ =  \frac{27 {f}^{4  \times 3}  {h}^{3} }{64 {h}^{9 \times 3} }   =  \frac{27 {f}^{12} {h}^{3} }{64 {h}^{27} }  \\  \\  \\  =  \frac{27 {f}^{12} }{64 {h}^{24} }

I hope I helped you^_^

5 0
3 years ago
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