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3 years ago

What is the difference between a pure substance and an impure substance, on a molecular scale?

1 answer:

7 0

pure substance:
elements:
they are made by one kind of atoms,, have their own properties cannot be broken down into simpler substances,,
compounds:
made by chemical reactions of elements joined together,,they have different properties has compared to the elements which make them in compounds elements may be separated by chemical means..
impure substances :
they are made by physical combinations,,and they may be separate by physical means ,,mixture is the example ,, also their properties do not change after becoming a mixture,,

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Write balanced equations for the reaction of each of the following carboxylic acids with NaOH. Part A formic acid Express your a

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Answer:

Part A

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Part B

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Explanation:

The reaction between an alkanoic acid and a base is a neutralization reaction. The reaction occurs as follows;

RCOOH + NaOH ----> RCOONa + H2O

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Explanation:

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3 years ago

Consider these generic half-reactions. Half-reaction E° (V) X+(aq)+e−⟶X(s) 1.52 Y2+(aq)+2e−⟶Y(s) −1.17 Z3+(aq)+3e−⟶Z(s) 0.84 Ide

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Answer:

strongest oxidizing agent: $X^{+}$

weakest oxidizing agent: $Y^{2+}$

strongest reducing agent: Y

weakest reducing agent: X

$X^{+}$ will oxidize Z

Explanation:

The higher the reduction potential of a species, higher will be the tendency to consume electrons from another species. Hence higher will be the oxidizing power of it's oxidized form and lower will be the reducing power of it's reduced form.

Alternatively, higher reduction potential value suggests that the oxidized form of the species acts as a stronger oxidizing agent and the reduced form of the species acts as a weaker reducing agent.

Order of reduction potential:

$E_{X^{+}\mid X}^{0}(1.52V)> E_{Z^{3+}\mid Z}^{0}(0.84V)> E_{Y^{2+}\mid Y}^{0}(-1.17V)$

So, strongest oxidizing agent: $X^{+}$

weakest oxidizing agent: $Y^{2+}$

strongest reducing agent: Y

weakest reducing agent: X

As reduction potential of the half cell $X^{+}\mid X$ is higher than the reduction potential of the half cell $Z^{3+}\mid Z$ therefore $X^{+}$ will oxidize Z into $Z^{3+}$ and itself gets converted into X.

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3 years ago

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Answer:

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Explanation:

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