Answer: Discover ZEISS Solutions
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The maximum amount of hydrogen gas that can be prepared is if all the hydrogen from both compounds is released.
The hydrogen in 4.94 g of SrH2 is calculated from the mass ratios between Sr and H
1) H2 in SrH2
Sr atomic mass = 87.62 g/mol
H2 molar mass = 2.02 g/mol
Mass of 1 mol of SrH2 = 87.62 g / mol + 2.02 g/mol = 89.64 g/mol
Ratio of H2 to SrH2 = 2.02 g H2 / 89.64 g SrH2
Proportion: 2.02 g H2 / 89.64 gSrH2 = x / 4.93 g SrH2
=> x = 4.93 g SrH2 * 2.02 g H2 / 89.64 g SrH2 = 0.111 g H2
2) H2 in H2O
2.02 g H2 / 18.02 g H2O * 4.14 g H2O = 0.464 g H2
3) Total mass of hydrogen = 0.111 g + 0.464 g = 0.575 g
Answer: 0.575 g
Answer:
pyruvic acid changes to alcohol and carbon dioxide.
Explanation:
In lactic acid fermentation, pyruvic acid from glycolysis changes to lactic acid. This type of fermentation is carried out by the bacteria in yogurt, and by your own muscle cells.
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Answer:
It must be large
Random
Explanation:
For a sample to represent a population accurately, it must be large and contain random sample spaces.
A population is a group of organism of the same species living in a particular place where they can reproduce.
- A sample must be representative of a given population
- By so doing, sampling space must be large so as to properly represent the species there in.
- The sampling must be done without any bias i.e. it must be randomly carried out.
Answer:
If temperature stays the same, the amount of carbon dioxide dissolved in the ocean would increase.
Explanation:
The carbon dioxide in the air (
) and the carbon dioxide dissolved in the ocean (
) are in a solution equilibrium:
.
Assume that the concentration of carbon dioxide in the air () increased while temperature stayed the same.
By Le Ch
atelier's Principle, the solution equilibrium would shift to offset this increase in concentration. Specifically, this equilibrium would reduce the amont of 
in the system by converting more atmospheric 
to 
dissolved in the ocean. Therefore, the concentration of 
dissolved in the ocean would increase.
