3 years ago

____ occurs when the vapor pressure of a liquid is equal to the external atmospheric pressure.

Chemistry

1 answer:

vaieri [72.5K]3 years ago

8 0

Answer:

huh be more clear

Explanation:

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HEMP ME ITS DUE BY MIDNIGHT

balu736 [363]

Answer:

Explanation:

Option B is the correct answer

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2 years ago

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Identify the solute and solvent in a dilute aqueous solution of potassium chloride

erastova [34]

Solute=potassium chloride, solvent=water

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3 years ago

On the basis of the information above, a buffer with a pH = 9 can best be made by using

telo118 [61]

Answer:

D H2PO4– + HPO42–

Explanation:

The acid dissociation constant for $\mathbf{H_3PO_4 , H_2PO^{-}_4 , HPO_4^{2-}}$ are $\mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \ 5\times 10^{-13}}$ respectively.

$\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}$

$\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}$

$\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}$

The reason while option D is the best answer is that, the value of pKa for both

$\mathbf{H_2PO^{-}_4 ,\ \& \ HPO_4^{2-}}$ lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.

Using Henderson-Hasselbach equation:

$\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}$

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3 years ago

The rate law for the decomposition of phosphine (PH3) is below. It takes 120. s for 1.00 M PH3 to decrease to 0.250 M. How much

Lubov Fominskaja [6]

Answer: 588.8 seconds

Explanation:

1.00 - 0.25 = 0.75M

4.00 - 0.320 = 3.68M

Therefore,

0.75M in 120 seconds

3.68M in x seconds

Cross multiply:

0.75*x = 120*3.68

x = 120*3.68/0.75

x = 588.8 seconds

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3 years ago

( BRAINLIEST)<br> Name the Salt formed by Sulfuric acid

mars1129 [50]

Answer:

sulfuric acid produces sulfate salts

please make me brainliest

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2 years ago