Answer:
f'(1)=150ln(1.5)
Step-by-step explanation:
I'm not sure why you would need a table since the limit definition of a derivative (from what I'm remembering) gives you the exact formula anyway... so hopefully this at least helps point you in the right direction.
My work is in the attachment but I do want to address the elephant on the blackboard real quick.
You'll see that I got to the point where I isolated the h's and just stated the limit equaled the natural log of something out of nowhere. This is because, as far as I know, the way to show that is true is through the use of limits going to infinity. And I'm assuming that you haven't even begun to talk about infinite limits yet, so I'm gonna ask you to just trust that that is true. (Also the proof is a little long and could be a question on it's own tbh. There are actually other methods to take this derivative but they involve knowing other derivatives and that kinda spoils a question of this caliber.)
Answer:
It will be any graphs that show a parallel line relationship.
Explanation:
Any graph that shows parallel lines will always be no solution.
Answer:
D. 4(2x² + 4x - 6); 130.0 inches
Step-by-step explanation:
Margot is sewing a ribbon on a seam along the perimeter of a square pillow. The side length of the pillow is 2x²+1 inches. She plans to make a similar pillow, including the ribbon, whose side length is 4x−7 inches. What expression can be used for the length of ribbon that she needs for both pillows, and what is the length if x = 3.5?
2x2+4x−6; 22.0 inches
2x2+4x−6; 32.5 inches
4(2x2+4x−6;) 88.0 inches
4(2x2+4x−6;) 130.0 inches
Perimeter of a square = 4 * side length
1- First square pillow
length = 2x²+1 in
Perimeter of first pillow = 4 * (2x²+1) in
Second square pillow
length = 4x-7 in
Perimeter of second pillow = 4(4x-7) in
Total ribbon length required = perimeter of first square pillow + perimeter of second square pillow
Total ribbon length required = 4(2x²+1) + 4(4x-7)
Factorise
4 is the common factor
=4(2x²+1)+(4x-7)
=4(2x²+1+4x-7)
=4(2x²+4x-6)
Total ribbon length required=4(2x²+4x-6)
If x=3.5
Total ribbon length required=4(2x²+4x-6)
=4{2(3.5)²+4(3.5)-6}
=4{2(12.25)+14-6)
=4(24.5+14-6)
=4(32.5)
=130.0 inches
Answer:
Step-by-step explanation:
the bearing of A from B is 065º. ... A boat sails from a
