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alexandr1967 [171]
3 years ago
12

Several different compounds can share the same empirical formula. The Molecular weight for three compounds with the empirical fo

rmula CH2O are:
1.)30.00
2.)60.00
3.)180.00

What is the Molecular formula of each compound?
Physics
2 answers:
Pie3 years ago
5 0

Molecular formulas:

  1. CH₂O;
  2. C₂H₄O₂;
  3. C₆H₁₂O₆.
<h3>Explanation</h3>

The empirical formula of a compound tells only the ratio between atoms of each element. The empirical formula CH₂O indicates that in this compound,

  • for each C atom, there are
  • two H atoms, and
  • one O atom.

The molecular weight (molar mass) of the molecule depends on how many such sets of atoms in each molecule. The empirical formula doesn't tell anything about that number.

It's possible to <em>add</em> more of those sets of atoms to a molecular formula to increase its molar mass. For every extra set of those atoms added, the molar mass increase by the mass of that set of atoms. The mass of one mole of C atoms, two mole of H atoms, and one mole of O atoms is 12.0 + 2\times 1.0 + 16.0 = 30.0\;\text{g}.

  • CH₂O- 30.0 g/mol;
  • C₂H₄O₂- 30.0 + 30.0 = 2 × 30.0 = 60.0 g/mol;
  • C₃H₆O₃- 30.0 + 30.0 + 30.0 = 3 × 30.0 = 90.0 g/mol.

It takes one set of those atoms to achieve a molar mass of 30.0 g/mol. Hence the molecular formula CH₂O.

It takes two sets of those atoms to achieve a molar mass of 60.0 g/mol. Hence the molecular formula C₂H₄O₂.

It takes \dfrac{180.0}{30.0} = 6 sets of those atoms to achieve a molar mass of 180.0 g/mol. Hence the molecular formula C₆H₁₂O₆.

jeka943 years ago
4 0

The atomic masses of the three elements of carbon,  hydrogen  and oxygen  in the molecule are 12, 1*2=2 and 16 respectively so molecular formula by adding these becomes 30

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(a) The magnitude of the force is 1.32 x 10⁻⁵ N and direction of the electric force on the sphere towards the right.

(b) The work done on the sphere by the electric force as it moves from A to B is 2.5 x 10⁻⁶ J.

(c) The change of the electric potential energy as the sphere moves from A to B is 2.5 x 10⁻⁶ J.

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The electric force on the sphere is calculated as follows;

F = Eq

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F = 300 x (44 x 10⁻⁹)

F = 1.32 x 10⁻⁵ N

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W = 1.32 x 10⁻⁵ N  x 0.189 m

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The work done on the sphere by the electric force as it moves from A to B is 2.5 x 10⁻⁶ J.

The change of the electric potential energy as the sphere moves from A to B is 2.5 x 10⁻⁶ J.

The potential difference between A and B is 56.7 V.

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