Answer:
a) 5 N b) 225 N c) 5 N
Explanation:
a) Per Coulomb's Law the repulsive force between 2 equal sign charges, is directly proportional to the product of the charges, and inversely proportional to the square of the distance between them, acting along the line that joins the charges, as follows:
F₁₂ = K Q₁ Q₂ / r₁₂²
So, if we make Q1 = Q1/5, the net effect will be to reduce the force in the same factor, i.e. F₁₂ = 25 N / 5 = 5 N
b) If we reduce the distance, from r, to r/3, as the factor is squared, the net effect will be to increase the force in a factor equal to 3² = 9.
So, we will have F₁₂ = 9. 25 N = 225 N
c) If we make Q2 = 5Q2, the force would be increased 5 times, but if at the same , we increase the distance 5 times, as the factor is squared, the net factor will be 5/25 = 1/5, so we will have:
F₁₂ = 25 N .1/5 = 5 N
All metals are good conductors.
Hope that helped you.
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Answer:
The change in momentum of the car is 30,000 kg m/s
Explanation:
Given,
The force exerted on the car to slow down, F = 7500 N
The time period of force, t = 4 s
The rate of change of momentum of the object is equal to the force acting on it.
Therefore,
<em> (mv - mu) / t = F</em>
Where v and u are the final and initial velocity of the car. The change in momentum of the car,
mv - mu = F x t
= 7500 x 4
= 30,000 kg m/s
Hence the change in momentum of the car is 30,000 kg m/s
