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4 years ago

Which method of heat transfer takes place when particles of matter vibrate and collide with each other in direct contact

Physics

2 answers:

Illusion [34]4 years ago

8 0

Answer:

Conduction of heat

Explanation:

The conduction of heat is defined as the movement of the internal heat energy within the same body due to the crashing and impact of atomic particles and the migration of electrons. This process occurs due to the direct contact of these minute particles.

The heat conduction takes place when any particular object is heated at a high-temperature. Due to this, the particles that are present inside the object acquires energy and starts vibrating. These molecules then flow in the adjacent areas transporting a certain amount of energy.

In the case of metals, the heat conduction takes place very efficiently. So they are considered to be a good conduction of heat.

Cerrena [4.2K]4 years ago

6 0

Conduction, hope this helps! :)

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A block with mass M = 3 kg is moving on a flat surface with constant speed v1 =

Alchen [17]

Answer:

this makes no since so i cant help you here sorry

5 0

2 years ago

A copper sphere 10 mm in diameter is dropped into a 1-m-deep drum of asphalt. The asphalt has a density of 1150 kg/m3 and a visc

kvasek [131]

Answer:

t = 1964636.542 sec

Explanation:

Given data:

sphere diameter is 10 mm

Density is 1150 kg/m^3

viscosity 105 N s/m^2

We knwo that time taken by sphere can be calculated by following procedure

$\tau = \mu \frac{du}{dy}$

$\frac{F}{A} = \mu \frac{du}{r}$

$\frac{\rho_C -\rho_{asphalt} gv}{2 \pi rL} = 10^5 \frac{du}{r}$

Solving for du

$du = \frac{ (8933 - 1150) 9.81 \frac{4}{3} \pi (10\times 10^{-3})^3}{2\pi \times 1\times 10^5}$

$du = u = 5.09\times 10^{-7}$

$u = \frac{1}{t}$

$t = \frac{1}{5.09\times 10^{-7}} = 1964636.542 sec$

6 0

4 years ago

Ladybug walks 10 cm forward and 5 cm backwards in 20 seconds what is the average speed of ladybug what is the average velocity

lbvjy [14]

Answer:

Average speed = 0.0075 m/s

Average velocity = 0.0025 m/s along forward direction

Explanation:

Speed is the ratio of distance and time and velocity is the ratio of displacement and time.

Distance traveled = 10 + 5 = 15 cm = 0.15 m

Displacement = 10 - 5 = 5 cm = 0.05 m

Time = 20 seconds

$\texttt{Average speed = }\frac{\texttt{Distance}}{\texttt{Time}}\\\\\texttt{Average speed = }\frac{0.15}{20}=7.5\times 10^{-3}m/s\\\\\texttt{Average velocity = }\frac{\texttt{Displacement}}{\texttt{Time}}\\\\\texttt{Average velocity = }\frac{0.05}{20}=2.5\times 10^{-3}m/s$

Average speed = 0.0075 m/s

Average velocity = 0.0025 m/s along forward direction

3 0

4 years ago

Read 2 more answers

You are operating a pwc in an area where swimmers are in the water. When must you slow your pwc to "slow, no wake speed"?.

Lostsunrise [7]

You should slow your pwc to "slow, no wake speed" when within 100 feet of anchored vessels or non-motorized craft.

This is the process of operating a personal watercraft at the slowest possible speed.

This helps to maintain steerage which prevents different forms of accident or risks when in motion in the water.

Read more about Slow-no-wake here brainly.com/question/10410716

#SPJ1

4 0

2 years ago

To get up on the roof, a person (mass 70.0kg) places a 6.00-m aluminum ladder (mass 10.0 kg) against the house on a concrete pad

Julli [10]

The magnitude of the forces acting at the top are;

$\mathbf{F_{Top, \ x}}$ = 132.95 N

$\mathbf{F_{Top, \ y}}$ = 0

The magnitude of the forces acting at the bottom are;

$\mathbf{F_{Bottom, \ x}}$ = $\mathbf{ F_f}$ = -132.95 N

$\mathbf{F_{Bottom, \ y}}$ = 784.8 N

The known parameters in the question are;

The mass of the person, m₁ = 70.0 kg

The length of the ladder, l = 6.00 m

The mass of the ladder, m₂ = 10.0 kg

The distance of the base of the ladder from the house, d = 2.00 m

The point on the roof the ladder rests = A frictionless plastic rain gutter

The location of the center of mass of the ladder, C.M. = 2 m from the bottom of the ladder

The location of the point the person is standing = 3 meters from the bottom

g = The acceleration due to gravity ≈ 9.81 m/s²

The required parameters are;

The magnitudes of the forces on the ladder at the top and bottom

The strategy to be used;

Find the angle of inclination of the ladder, θ

At equilibrium, the sum of the moments about a point is zero

The angle of inclination of the ladder, θ = arccos(2/6) ≈ 70.53 °C

Taking moment about the point of contact of the ladder with the ground, <em>B </em>gives;

$\sum M_B$ = 0

Therefore;

$\sum M_{BCW}$ = $\sum M_{BCCW}$

Where;

$\sum M_{BCW}$ = The sum of clockwise moments about <em>B</em>

$\sum M_{BCCW}$ = The sum of counterclockwise moments about <em>B</em>

Therefore, we have;

$\sum M_{BCW}$ = 2 × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81

$\sum M_{BCCW}$ = $F_R$ × √(6² - 2²)

Therefore, we get;

2 × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81 = $F_R$ × √(6² - 2²)

$F_R$ = (2 × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81)/(√(6² - 2²)) ≈ 132.95

The reaction force on the wall, $F_R$ ≈ 132.95 N

We note that the magnitude of the reaction force at the roof, $F_R$ = The magnitude of the frictional force of bottom of the ladder on the floor, $F_f$ but opposite in direction