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3 years ago

A woman begins driving her car 25 km north of calgary. Some time later, the woman and her car are 100 km north of calgary.

1 answer:

5 0

Both the distance and displacement of the woman's drive are 75 km.

You find this by reducing 25 from 100.

We know that the distance and displacement are the same because she continues to go in the same direction (north) for the whole trip, and makes no turns that we know of.

Hope this helps! <3

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A concrete block is hung from an ideal spring that has a force constant of 100 N/m . The spring stretches 0.129 m .A- What is th

madam [21]

Answer:

1.31498 kg

0.72050 s

Explanation:

m = Mass of block

g = Acceleration due to gravity = 9.81 m/s²

k = Spring constant = 100 N/M

x = Displacement = 0.129 m

The force balance is

$mg=kx\\\Rightarrow m=\dfrac{kx}{g}\\\Rightarrow m=\dfrac{100\times 0.129}{9.81}\\\Rightarrow m=1.31498\ kg$

The mass of the block is 1.31498 kg

Time period is given by

$T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{1.31498}{100}}\\\Rightarrow T=0.72050\ s$

The period of oscillations is 0.72050 s

The time period does not depend on the acceleration due to gravity. It varies with the mass and the spring constant.

Hence, the time period would be the same

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3 years ago

A mother and her young child want to play on a seesaw at a playground. The child sits on the end of one side of the seesaw. Wher

EleoNora [17]

Answer:middle

Explanation:

Because it will make the seasaw balanced

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3 years ago

if researchers hit a sheet of metal with a yellow light and nothing happens, what color should the try next?

Nataliya [291]

The photoelectric emission is possible if the wavelength of the incident light is less than that of yellow light

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4 years ago

You push a 1.30 kg physics book 2.80 m along a horizontal tabletop with a horizontal push of 1.55 N while the opposing force of

Rzqust [24]

Answer:

Explanation:

Step one:

given data

mass m= 1.3kg

distance moved s= 2.8m

opposing frictional force= 0.34N

assume g= 9.81m/s^2

we know that work done= force *distance moved

1. work done to push the book= 1.55*2.8=4.34J

2. Work against friction = force of friction x distance

= 0.34*2.8=0.952J

Step two:

the work done on the book is the net work, which is

Network done= work done to push the book- Work against friction

Network done= 4.32-0.952=3.36J

<u>Therefore the work of the 1.55N 3.36J</u>

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3 years ago

What type of tide occurs when the sun, moon, and earth form a right triangle in space?

stiks02 [169]

Neap tide is your answer

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3 years ago