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Elan Coil [88]
3 years ago
8

What is the point of intersection when the system of equations below is graphed on the coordinate plane?

Mathematics
1 answer:
lora16 [44]3 years ago
5 0

Answer:

<h2>not exist</h2>

Step-by-step explanation:

The coordinates of the intersection of the line are the solution of the system of equations.

\underline{+\left\{\begin{array}{ccc}x-y=1\\y-x=1\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad0=2\qquad\bold{FALSE}

The system of equations has no solution. Therefore, the lines are parallel (the intersection does not exist).

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Help me please, I’ll give brainliest!!
polet [3.4K]

Answer:

A line that is perpendicular to y=2/5x-5 must have a slope of -5/2, but a line parallel to line y=5/2x+6 must have a slope of 5/2, and these slopes do not match up.

Explanation:

In order for a line to be parallel to another line, they must have the same slope. In order for a line to be perpendicular to another line, their slopes must be opposite reciprocals (meaning that when they are multiplied, the product is -1). From here you can find what slope the line must have to perpendicular or parallel to another line, and then you can see that the answers to not match up to be the same line!

Hope this helped :)

5 0
3 years ago
Something divide -7 = -14
Zina [86]

Answer:

98

Step-by-step explanation: Inverse operations

-14 x -7 = 98

98 / 7 = 14

98 / -7 = -14

7 0
3 years ago
Round 76070.7376413 to 2 decimal places
lakkis [162]
<h3>Answer:</h3><h2>76,070.74</h2><h3>Step-by-step explanation:</h3>

When you round decimals, your looking at the place value, then your looking at the place value next to it.

<u>If you see a number that is 0 - 4 behind the place value your rounding to, you do nothing to the place value.</u>

<u>If you see a number that is 5 - 9 behind the place value your rounding to, you add one to the place value.</u>

<h3><u>Example 1:</u></h3>

Round the Number 71.25 to the <u>Tenths place.</u>

<u>When we go to the place value, Tenths, we go behind the Tenths place value:</u>

71.<em>2</em><u>5</u>

<u>2 is the Tenths place value, 5 is the place value behind the Tenths place value.</u>

<u>Since 5 is able to be rounded up, you add one to the tenths place.</u>

<u>It should be rounded to 71.3. There cannot be numbers where you've rounded, just zeroes.</u>

<h3><u>Example 2:</u></h3>

Round the Number <u>3,345.8493</u> to the <u>Thousands place.</u>

3 is the Thousands place, 3 is the place value behind the Thousands place value.

3 is not in between 5 - 9. So, the rounded answer is 3,000.

When numbers behind the Place Value cannot round the Thousands place value, it turns into zeroes too.

Answer:

Round  76070.7376413 to the Hundredths place value.

The 3 is the Hundredths place value, the 7 is the place value behind the Hundredths place value.

7 qualifies for the numbers 5 - 9.

Therefore, you add 1 to the hundredths place value.

Your final answer is (76,070.74)

Best of Luck to you.

If you have any questions, feel free to comment below.

Merry Christmas!

8 0
3 years ago
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
B) Matumba's can shoot 60% from the free throw line. If he shot 30 times, how many free
Pani-rosa [81]
I know the correct answer but I need you to answer my questions first
6 0
3 years ago
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