3 years ago

Write the equation of a line perpendicular to y=2x-5y=2x−5 that passes through the point (2, -5).

Mathematics

1 answer:

EleoNora [17]3 years ago

7 0

Answer:

y= -1/2x-5

Step-by-step explanation:

The reciprocal of 2 is -1/2, and the y-intercept given is -5. Given those, the equation is y= -1/2x - 5

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Prove the identity secxcscx(tanx+cotx)=2+tan^2x+cot^2x

svetlana [45]

Hello,

$sec(x)= \dfrac{1}{cos(x)} \\

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