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3 years ago

Anybody know the answer?

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

4 0

It is 5 ft east and 9 ft north of its starting place, so the distance can be found by the Pythagorean theorem to be the root of the sum of the squares of the east and north distances:

... x = √(5² +9²) ft = √106 ft ≈ 10.3 ft

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Anyone want to f riend me or cha t here

vovangra [49]

Answer:

yes

Step-by-step explanation:

yes I want ☺️☺️☺️☺️☺️☺️

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2 years ago

Read 2 more answers

PLEASE HELP!!!!!PLEASE.

alisha [4.7K]

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3 years ago

HELP PLEASE! and give out good answers.

zhuklara [117]

I think its A. There is a peak in the orders from 6 to 10 pounds

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3 years ago

An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you th

aliya0001 [1]

Answer:

0.227 = 22.7% probability that the mean printing speed of the sample is greater than 18.12 ppm.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 17.42 ppm and a standard deviation of 3.25 ppm.

This means that $\mu = 17.42, \sigma = 3.25$

Sample of 12:

This means that $n = 12, s = \frac{3.25}{\sqrt{12}}$

Find the probability that the mean printing speed of the sample is greater than 18.12 ppm.

This is 1 subtracted by the p-value of Z when X = 18.12.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{18.12 - 17.42}{\frac{3.25}{\sqrt{12}}}$

$Z = 0.75$

$Z = 0.75$ has a pvalue of 0.773.

1 - 0.773 = 0.227

0.227 = 22.7% probability that the mean printing speed of the sample is greater than 18.12 ppm.

4 0

3 years ago

Jack wants to know how many families in his small neighborhood of 60 homes would help organize a neighborhood fund-raising party

seraphim [82]

hello,

Jack wants to know how many families in his small neighborhood of 60 homes would help organize a neighborhood fund-raising party. He put all the addresses in a bag and drew a random sample of 30 addresses. He then asked those families if they would help organize the fund-raising party. He found that 12% of the families would help organize the party. He claims that 12% of the neighborhood families would be expected to help organize the party. Is this a valid inference?

Yes, this is a valid inference because the 30 families speak for the whole neighborhood

it's the correct one because if he ask 30 families so they talk to their neighborhood so its will be 60 ;) so its correct,

hope this help

7 0

3 years ago