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zhuklara [117]
2 years ago
9

The diagram below shows the temperature dropping from 80°C to 20°C.

Chemistry
2 answers:
Neko [114]2 years ago
8 0

Answer:

Kinetic energy decreases as temperature decreases.

Explanation:

From the description that the system at 80°C has longer arrows, or move faster than the system at 20°C, having shorter actors indicating a slower motion, we can conclude that the kinetic energy of a body depends on its temperature.

If the system at 80°C shows a greater kinetic energy (faster motion of particles) than the system at 20°C, it then implies that decreasing the temperature of the body decreases its kinetic energy.

dexar [7]2 years ago
3 0

Answer:

C on edge

Explanation:

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Which of the following substances would have the highest dispersion forces? Why?
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Answer:

Si

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Dispersion force or London force is the force of attraction between two atoms or molecules in a substance in solid , liquid and gas . In gas , this force is minimum and in solid this force is maximum . In solid this force is maximum in metals in which this force forms  metallic bond .

Among the given substances , Si , Sn , MgO , C₂₀H₄₂ are solid , so dispersion force will be high in them .

Among all as mentioned above , Si will have highest dispersion force . It is due to four covalent bond that bind two atoms of Si in solid silicon . Its three dimensional crystal structure consist of silicon atoms , all bound by four covalent bonds .

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1 year ago
What is the molar concentration of Na (aq) in a solution that is prepared by mixing 10 mL of a 0.010 M NaHCO3(aq) solution with
postnew [5]

Explanation:

Total volume of the solution will be (10 ml + 10 ml) = 20 ml. As there are 1000 ml in 1 L. So, 20 ml will be equal to 0.02 L.

As molarity equals number of moles divided by volume in liter. Hence, calculate number of moles of NaHCO_{3} as follows.

        No. of moles = M_{NaHCO_{3}} \times V_{NaHCO_{3}}

                              = 0.010 \times 0.01 L

                              = 10^{-4} mol

Hence, moles of Na^{+} will also be equal to 10^{-4} mol.

Now, calculate the no. of moles of Na_{2}CO_{3} as follows.

         No. of moles = M_{Na_{2}CO_{3}} \times V_{Na_{2}CO_{3}}

                               = 0.010 M \times 0.01 L

                               = 10^{-4} mol

As there are 2 Na^{+} ions in 1 mole of Na_{2}CO_{3}. Hence, in 10^{-4} mol number of Na^{+} ions will be 2 \times 10^{-4} mol.

When both the solutions are mixed together then molarity of the solution will be calculated as follows.

                 Molarity of solution = \frac{total Na^{+} ions}{\text{total volume}}

                                = \frac{3 \times 10^{-4}}{0.02L}

                                = 0.015 M  

Thus, we can conclude that the molar concentration of Na (aq) in the given solution is 0.015 M.

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