No, because hydrogen isn’t brought out of the equation
It turns liquid to gas. Hoped this helped!!
Without being given a temperature or amount of solute, it's not as easy to find the level of saturation. If there is excess of solvent in the beaker, the solution is unsaturated. In this case, the solution is clear so there is no indication of excess of solute or solvent. Therefore, the solution is saturated.
The reaction is,
H2S + I2 --------------> 2 HI +S
Molar weight of H2S = 34 g per mol
Molar weight of HI =128 g per mol
Molar weight of I2 =254 g per mol
Moles of H2S in 49.2 g = 49.2 /34 mol = 1.447 mol
So according to stoichiometry of the reaction, number of I2 mols needed
= 1.447 mol
The mass of I2 needed = 1.447 mol x 254 g
