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3 years ago

5

A picture frame made from a strip of wood is 2 inches wide the frame is rectangular and the outside of its measures is 12 inches

by 20 inches what is the total area of the wood part of the frame in square inches
A. 60 square inches
B. 112 square inches
C. 128 square inches
D. 236 square inches

2 answers:

torisob [31]3 years ago

8 0

C I think !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

ki77a [65]3 years ago

6 0

Answer:

Area of Frame = 60 in^2

Step-by-step explanation:

The total area ("outside") is 20 in times 12 in, or 240 in^2.

The area of the opening is 10 in by 18 in, or 180 in^2.

Subtracting the latter from the former, we get

Area of Frame = 60 in^2

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Daniel works at an electronics store, and he claims that the popularity of a television (measured in number of sales) is inverse

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We are given that popularity of television is inversely proportional to its cost.

let us say popularity of television is represented by "P" and cost of television by "T".

We will use a constant "k" to convert the proportionality sign to equal to (=) sign.

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Colt1911 [192]

Answer:

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Step-by-step explanation:

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2 years ago

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If each quadrilateral below is a parallelogram, find the missing measures.

prisoha [69]

Step-by-step explanation:

We will use parallelogram properties to answer our given problems.

(1) Since we know that opposite sides of parallelogram are congruent, therefore measure of side MN and side KN will be equal to the measure of their opposite sides.

LM=KN and KL=MN

Upon substituting our given values we will get,

45=KN and 31=MN

Property: The opposite angles of parallelogram are congruent and consecutive angles are supplementary.

We have been given $m\angle N=119^{o}$ , therefore $m\angle L=119^{o}$ .

We will find measure of angle K by using supplementary angles.

$m\angle N+m\angle M=180^{o}$

$119^{o}+m\angle M=180^{o}$

$m\angle M=(180-119)^{o}$

$m\angle M=61^{o}$

By opposite angles of parallelogram $m\angle K=61^{o}$ .

(2) Opposite sides of parallelogram are equal. Therefore, CF=DE and FE=CD.

Upon substituting our given values we will get,

CF=10 and FE=15.

Property: Diagonals of parallelogram bisect each other.

So CE will be 2 times CG and GD will be half the length of FD.

$CE=2\times 7=14$

$GD=\frac{1}{2}\times 22=11$

(3) Property: Opposite sides of parallelogram are congruent.

$SR=PQ$ and $QR=PS$

Upon substituting our given values we will get,

$SR=24$ and $QR=19$

Property: Diagonals of parallelogram bisect each other.

So SQ will be 2 times TQ and PT will be half the length of PR.

$SQ=2\times 10=20$

$PT=\frac{1}{2}\times 42=21$

Property: The opposite angles of parallelogram are congruent and consecutive angles are supplementary.

$m\angle PQR=106^{o}$

$m\angle PQS=m\angle QSR$ Alternate interior angles.

$m\angle PQS=49^{o}$

$m\angle QRS=m\angle QPS$ Opposite angles of parallelogram.

$m\angle PQR+m\angle QPS=180^{o}$

$106^{o}+m\angle QPS=180^{o}$

$m\angle QPS=180^{o}-106^{o}$

$m\angle QPS=74^{o}$

Therefore, measure of angle QRS will 74 degrees.

$m\angle PRS=m\angle QPR$ Alternate interior angles.

$35^{o}=m\angle QPR$

$m\angle RPS=74^{o}-m\angle QPR$

$m\angle RPS=74^{o}-35^{o}$

$m\angle RPS=39^{o}$

Now let us find measure of angle PSQ.

$m\angle PSQ=m\angle PQR-m\angle QSR$

$m\angle PSQ=106^{o}-49^{o}$

$m\angle PSQ=57^{o}$

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