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Inessa [10]
2 years ago
13

Is 1/3 greater than 5/6

Mathematics
1 answer:
Harman [31]2 years ago
5 0
1/3 or 5/6 

Lets make the fractions into decimals. To make a fraction into decimal you have to divide the numerator by the denominator. The numerator is the top part of a fraction and the denominator is the bottom part of the fraction. 

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

Calculations

1/3
1 ÷ 3 =  0.3333.... 

5/6 
5 ÷ 6 = 0.83333...

0.83333... is greater then 0.3333.....
Therefore 5/6 is greater then 1/3 
1/3 is smaller then 5/6 
You might be interested in
Solve log base 6 (x-6) - log base 6 (x + 4) = 2
Ray Of Light [21]

Answer:

no solutions

Step-by-step explanation:

Since the two terms have the same base, we are able to use the rule for subtracting logarithms:

log_{b}(x) - log_{b}(y) = log_{b}(\frac{x}{y} )

Therefore, the equation can be written as:

log_{6}(\frac{x-6}{x+4} )=2

By using the definition of a logarithm we can say that:

\frac{x-6}{x+4} = 6^{2}\\\frac{x-6}{x+4} = 36\\x -6 = 36x+144\\35x = -150\\x =-\frac{30}{7}

When plugging this solution in, you find that the term log_{6}(x-6) has x-6 evaluate to a number less than 0. This is not included in the domain of log functions, so -\frac{30}{7} is not a valid solution. This means that there are no solutions.

4 0
1 year ago
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
Select the correct answer.
Irina18 [472]
D. About 122 units I just took the test
4 0
2 years ago
I will cash app u $20 dollars show your work thank u
kolezko [41]

Answer:

hmm.. very blurry repost please

Step-by-step explanation:

3 0
2 years ago
2. The sum of two numbers is 51 and the greater number is twice the smaller number. Find the numbers aj set up the variables (2
storchak [24]

Answer:

Larger number = 34

Smaller number = 17

Step-by-step explanation:

Given that:

Sum of numbers = 51

Let,

x be the larger number

y be the smaller number

According to given statement;

x+y=51       Eqn 1

x = 2y        Eqn 2

Putting x=2y in Eqn 1

2y+y=51

3y=51

Dividing both sides by 3

\frac{3y}{3}=\frac{51}{3}\\y=17

Putting y=17 in Eqn 2

x=2(17)

x=34

Hence,

Larger number = 34

Smaller number = 17

7 0
3 years ago
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