How do you simplify 2i<6u
1 answer:
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Answer:
Step-by-step explanation:
The relevant rule of exponents is ...
(a^b·c^d)^e = a^(be)·c^(de)
Then ...
(m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)
= m^(35/12)·n^(-28/15)
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Since you want positive rational exponents, you can write this as ...
= m^(35/12)/n^(28/15)
<h3><u>Answer</u> :</h3>
For triangle : A + B + C = π
⇒ A + B = π - C
⇒ cot(A + B) = cot(π - C)
⇒
⇒
<u>Now 1st part of the given expression</u>!
⇒
⇒
⇒
⇒ 1 - cotB cotC
<u>Similarly 2nd part</u>!
⇒ 1 - cotA cotB
<u>Similarly 3rd part</u>!
⇒ 1 - cotC cotA
<u>LHS</u> :
= <u>RHS</u>