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enyata [817]
3 years ago
13

A time for the 100 meter sprint of 14.9 seconds at a school where the mean time for the 100 meter sprint is 17.6 seconds and the

standard deviation is 2.1 seconds. Find the z-score corresponding to the given value and use the z-score to determine whether the value is unusual. Consider a score to be unusual if its z-score is less than -2.00 or greater than 2.00.
Mathematics
1 answer:
kirza4 [7]3 years ago
6 0

Answer:

Z-score = -1.285

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 17.6 seconds

Standard Deviation, σ = 2.1 seconds

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

For x = 14.9, we have:

z_{score} = \displaystyle\frac{14.9-17.6}{2.1} = -1.285

A z-score to be unusual if its z-score is less than -2.00 or greater than 2.00.

Thus, the z-score is not unusual as it lies in the range [-2.00, 2.00]

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Solve for e

d = 1/e + 1/f

Move 1/f to the left side of the = sign

d - 1/f = 1/e

Multiply each side by e

e(d - 1/f) =  e(1/e)

e(d - 1/f) = 1

Divide out (d - 1/f)

e(d - 1/f) / (d - 1/f) = 1 / (d - 1/f)

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3 years ago
HELP with these questions
zlopas [31]

<u>Step-by-step explanation:</u>

transform the parent graph of f(x) = ln x        into f(x) = - ln (x - 4)  by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

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          <u> +4 </u>  <u>    +4 </u>

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(5, 0)

(???, 1): 1 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

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             e = x - 4

          <u> +4 </u>   <u>    +4 </u>

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          6.72 = x

(6.72, 1)

Domain: x - 4 > 0

                <u>  +4 </u>  <u>+4  </u>

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No vertical asymptotes

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transform the parent graph of f(x) = 3ˣ        into f(x) = - 3ˣ⁺⁵  by shifting the parent graph 5 units to the left and reflecting over the x-axis

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(-∞, ∞)

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Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

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En ampliar o reducir una fotografía, obtenemos copias de la fotografía original, pero de medida diferente. Si la anchura del ori
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Answer:

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