6.4 * 6.02 * 10^23 = 3.8528*10^24 atoms
Don't let the fact that it's vanadium throw you off, avagadros constant stays the same for all elements
Image #1 is clearly sharing their electrons to complete an octet, which makes me believe it is a Double Bond.
Image #2 is a duplicate (if my computer is displaying this picture correctly) which if this is the case and my computer isn't the issue I'd say it is a Double Bond. I don't think "above" and "below" make a difference but it may depend on the attachments and where they were originally placed. Either way Image #1 and #2 are Double Bonds.
Image #3 if I recall accurately is where 4 valence electrons must be gained. I'm a bit fuzzy with valence electrons and recommended viewing Crash Course on this if you'd like to perfect your understanding on Valence Electrons, but I recall a similar question and I remember 4 valence electrons for this type of image. Wish I could help more on this. :(
Answer:
Selenium
Explanation:
One way to figure this out is to count the electrons and add them up.
2+2+6+2+6+2+10+4 = 34 electrons
A neutral atom has the same number of electrons and protons. Protons tell us the atomic number of an element. Element number 34 is Selenium.
Another way to figure it out is to look at just the highest "s" or "p" level of the electron configuration, and then see which element corresponds to that. This element has a 4s and a 4p, so I will look at 4p. The configuration is 4p4, so I will look at the 4th row of the periodic table (4p4) in the "p" block (4p4) and the 4th element in the "p" block (4p4). That's selenium :)
Answer:
1 mol of CH₄ will contain greatest mass of the oxygen i.e 4 grams
Explanation:
Given;
1 mol of CH₄
0.6 mol of C₆H₆
0.4 Mol of C₃H₈.
Now,
moles = Mass / Molar mass
Thus,
for 1 mol of CH₄
1 = mass / ( 12 + 4 × (1) )
or
mass = 16 grams
now,
16 grams of CH₄ contains 4 grams of hydrogen
and, for 0.6 mol of C₆H₆
0.6 = Mass / ( 12 × 6 + 6 × 1)
or
Mass = 46.8 grams
Now,
78 grams of CH₄ contains 6 grams of hydrogen
thus,
46.8 grams of CH₄ will contain = (6 / 78) × 46.8 grams of hydrogen
or
46.8 grams of CH₄ will contain = 3.6 grams of hydrogen
and, for 0.4 Mol of C₃H₈
0.4 = mass / (3 × 12 + 8 × 1)
or
Mass of 0.4 Mol of C₃H₈ = 17.6 grams
Now,
44 grams of C₃H₈ contains 8 grams of hydrogen
thus,
17.6 grams of C₃H₈ will contain = ( 8 / 44 ) × 17.6 grams of hydrogen
or
17.6 grams of C₃H₈ will contain = 3.2 grams of hydrogen
Hence,
1 mol of CH₄ will contain greatest mass of the oxygen i.e 4 grams
Answer:
Sorry dont know Good Luck.
Explanation: