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Slav-nsk [51]
3 years ago
15

How many atoms are in 6.4 moles of vanadium

Chemistry
1 answer:
den301095 [7]3 years ago
3 0
6.4 * 6.02 * 10^23 = 3.8528*10^24 atoms
Don't let the fact that it's vanadium throw you off, avagadros constant stays the same for all elements
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Chemical reaction when chromium metal is immersed in an aqueous solution of cobalt(II) chloride.
Marrrta [24]

2Cr + 3CoCl_2→ 2CrCl_3 + 3Co

Explanation:

  • The products formed are chromic chloride and cobalt.

        Chromium + Cobaltous Chloride = Chromic Chloride + Cobalt

  • Type  of reaction is Single Displacement (Substitution) which is there is a displacement of one atom.

Reactants used in the reaction are -

  • Chromium(Cr)
  • Cobaltous Chloride (CoCl_2)

Products formed in the reaction are -

  • Chromic Chloride(CrCl_3)
  • Cobalt (Co)

Hence, the chemical reaction is as follows -

  • Cr + CoCl_2 →CrCl_3 + Co

For balancing the above chemical equation we need to add a coefficient of 2 in front of chromium and of 3 in front of cobalt(II)chloride on right-hand-side while of 2 in front of chromium chloride and of 3 in front of carbon monoxide on left-hand-side of the equation.

Hence, the balanced equation is -

2Cr + 3CoCl_2→ 2CrCl_3 + 3Co

3 0
3 years ago
Conversion of minus 1 coulomb meter in debye
Viktor [21]

Answer:

-1 Coulomb meter = -2.997 × 10²⁹ Debye

Explanation:

Given:

Coulomb meter = -1 CM

Find:

In debye

Computation:

We know that,

1 Coulomb meter = 299,792,458,178,090,000,000,000,000,000 Debye

So,

-1 Coulomb meter = -299,792,458,178,090,000,000,000,000,000 Debye

-1 Coulomb meter = -2.997 × 10²⁹ Debye

3 0
3 years ago
Given that the molar mass of NaNO3 is 85.00 g/mol, what mass of NaNO3 is needed to make 4.50 L of a 1.50 M NaNO3 solution?
marissa [1.9K]
Mass = molarity x molar mass( NaNO₃) x volume

mass = 1.50 x 85.00 x 4.50

mass = 573.75 g of NaNO₃

hope this helps!
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