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Slav-nsk [51]
3 years ago
15

How many atoms are in 6.4 moles of vanadium

Chemistry
1 answer:
den301095 [7]3 years ago
3 0
6.4 * 6.02 * 10^23 = 3.8528*10^24 atoms
Don't let the fact that it's vanadium throw you off, avagadros constant stays the same for all elements
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Why don't siblings look exactly alike
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Your genes play a big role in making you who you are. ... But brothers and sisters don't look exactly alike because everyone (including parents) actually has two copies of most of their genes. And these copies can be different. Parents pass one of their two copies of each of their genes to their kids.

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What do chemists measure concentration with?
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How to calcutate concentration of solution.
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3 years ago
1.5 moles are present in 60.0 grams of calcium.
Andrew [12]

Answer:

True.

Explanation:

To know which option is correct, let us calculate the number of mole present in 60g of calcium. This is illustrated below:

Mass of Ca = 60g

Molar Mass of Ca = 40g/mol

Number of mole Ca =....?

Number of mole = Mass/Molar Mass

Number of mole of Ca = 60/40

Number of mole Ca = 1.5 moles.

From the calculations made above, we can see that 1.5 moles are present in 60.0 grams of calcium

3 0
3 years ago
Assume the molality of isoborneol in your product is 0.275 mol/kg. What is the melting point of your impure sample given that th
aliina [53]

Answer:

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = ?

Depression in freezing point = \Delta T_f

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample  = 0.275 mol/kg

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  non electrolyte)

\Delta T_f=1\times 40^oC kg/mol\times 0.275 mol/kg

\Delta T_f=11^oC

\Delta T_f=T- T_f

T_f=T- \Delta T_f=179^oC-11^oC=168^oC

168°C is the melting point of your impure sample.

4 0
3 years ago
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